NCERT Solutions Ganita Prakash (Part 1) Chapter 3 –56Section 3.3 A Hundredth Part — In-text Questions

Book page 55 Updated on2026-09-05

Q1.
In each group, identify the longest and the shortest lengths. Mark each length on the scale. (a) 3/10, 3/100, 33/100 (b) 3 1/10, 30/10, 1 3/10 (c) 45/100, 54/100, 5/10, 4/10 (d) 3 6/10, 3 6/100, 3 6/10 6/100 (e) 8/10 2/100, 9/100, 1 8/100 (f) 7 3/10 5/100, 7 5/10, 7 41/100 (g) 65/10 15/100, 5 87/100, 5 7/100
Answer

Write every length in hundredths (or as a decimal) and then compare like whole numbers.

GroupValues in decimal formLongestShortest
(a)0.30, 0.03, 0.33331003100
(b)3.1, 3.0, 1.33 1101 310
(c)0.45, 0.54, 0.50, 0.4054100410
(d)3.60, 3.06, 3.663 610 61003 6100
(e)0.82, 0.09, 1.081 81009100
(f)7.35, 7.50, 7.417 5107 310 5100
(g)6.65, 5.87, 5.076510 151005 7100

Marking them on the scale. Count small divisions from the labelled mark:

  • (a) scale 0 to 1: 3100 is the 3rd small mark, 310 the 30th, 33100 the 33rd.
  • (b) scale 0 to 10: mark 1.3, 3.0 and 3.1.
  • (c) scale 0 to 1: mark 0.40, 0.45, 0.50 and 0.54.
  • (d) scale 3010 to 4010: 3.06 sits just after 3.0, 3.60 on the 3610 mark, 3.66 six small marks later.
  • (f) scale 6810 to 7810: mark 7.35, 7.41 and 7.50.
Why it happens: once all the lengths are converted to the same small unit, the comparison is ordinary counting. In (d) the trap is 3 610 = 3.60 against 3 6100 = 3.06 — the 6 is worth ten times more in the first one.
Check it yourself: two of the printed scales are too short for their own group — in (e) the scale runs only from 0 to 1, so 1 8100 falls just beyond its right end, and in (g) the scale starts at 5710, so 5 7100 falls before its left end. Extend the scale a little in your notebook and then mark them.
Was this helpful? Report an error