NCERT Solutions Ganita Prakash (Part 1) Chapter 4 –93Section 4.4 Simplification of Algebraic Expressions — In-text Questions

Book page 91 Updated on2026-09-05

Q1.
Could we have written the initial expression as (40x + 75y) + (– 6x – 10y)?
Answer

Yes. Subtracting an expression is the same as adding its opposite.

– (6x + 10y) = – 6x – 10y
So (40x + 75y) – (6x + 10y) = (40x + 75y) + (– 6x – 10y)
= 34x + 65y either way
Why it happens: Every subtraction can be turned into an addition of the opposite number. Written as a sum of terms, an expression becomes much easier to swap and group.
Q2.
Example 8: Charu’s scores in three rounds of a quiz are 7p – 3q, 8p – 4q, and 6p – 2q, where p is the score for a correct answer and q the penalty for an incorrect answer. What do each of the expressions mean?
Answer
RoundExpressionWhat it says
17p – 3q7 correct answers and 3 wrong answers
28p – 4q8 correct answers and 4 wrong answers
36p – 2q6 correct answers and 2 wrong answers
Why it happens: Each correct answer earns p marks, so 7 of them earn 7p. Each wrong answer costs q marks, so 3 of them cost 3q — a subtraction.
Q3.
If the score for a correct answer is 4 (p = 4) and the penalty for a wrong answer is 1 (q = 1), find Charu’s score in the first round.
Answer
7p – 3q = 7 × 4 – 3 × 1
= 7 × 4 + (–3 × 1)
= 28 + (–3)
= 25
Q4.
What are her scores in the second and third rounds?
Answer

Use p = 4 and q = 1 in each expression.

Round 2: 8p – 4q = 8 × 4 – 4 × 1 = 32 – 4 = 28
Round 3: 6p – 2q = 6 × 4 – 2 × 1 = 24 – 2 = 22
Check it yourself: 25 + 28 + 22 = 75, and we will see below that her total is 21p – 9q = 84 – 9 = 75. ✔
Q5.
What if there is no penalty? What will be the value of q in that situation?
Answer

No penalty means nothing is taken away for a wrong answer.

q = 0
Round 1 score becomes 7p – 3 × 0 = 7p = 28
Total becomes 21p – 9 × 0 = 21p = 84
Why it happens: Putting q = 0 makes every penalty term vanish, because any number multiplied by 0 is 0.
Q6.
What is her final score after the three rounds?
Answer

Add the three round scores and simplify.

(7p – 3q) + (8p – 4q) + (6p – 2q)
= 7p + (–3q) + 8p + (–4q) + 6p + (–2q)
= 7p + 8p + 6p + (–3q) + (–4q) + (–2q) (swapping and grouping)
= (7 + 8 + 6)p – (3 + 4 + 2)q
= 21p – 9q
Q7.
Give some possible scores for Krishita in the three rounds so that they add up to give 23p – 7q.
Answer

Split 23 into three parts and 7 into three parts.

One possibility:
Round 1: 8p – 3q
Round 2: 7p – 2q
Round 3: 8p – 2q
Sum = (8 + 7 + 8)p – (3 + 2 + 2)q = 23p – 7q
Try This: Another set is 10p – 4q, 6p – 1q and 7p – 2q. Make up a third set of your own — there are many.
Q8.
Can we say who scored more? Can you explain why? (Charu: 21p – 9q, Krishita: 23p – 7q)
Answer

Krishita scored more.

Krishita has 23p, Charu has 21p → Krishita gains 2p more
Krishita loses 7q, Charu loses 9q → Krishita loses 2q less
Why it happens: Krishita wins on both counts — more correct answers and fewer wrong ones. Since p and q are positive numbers, her total must be larger, whatever the marking scheme is.
Q9.
How much more has Krishita scored than Charu? Simplify this expression further: 23p – 7q – (21p – 9q)
Answer
23p – 7q – (21p – 9q)
= 23p – 7q – 21p + 9q
= 23p – 21p + (–7q) + 9q
= (23 – 21)p + (9 – 7)q
= 2p + 2q
Check it yourself: With p = 4 and q = 1, Krishita has 92 – 7 = 85 and Charu has 84 – 9 = 75. The difference is 10, and 2p + 2q = 8 + 2 = 10. ✔
Q10.
Example 9: Simplify the expression 4 (x + y) – y
Answer
4 (x + y) – y
= 4x + 4y – y (distributive property)
= 4x + 4y + (– y)
= 4x + (4 – 1)y
= 4x + 3y
Why it happens: 4 times a sum is the sum of 4 times each part. After that, 4y and –y are like terms, and 4y – y is 3y.
Q11.
Example 10: Are the expressions 5u and 5 + u equal to each other?
Answer

No. They describe two different operations.

5u means 5 times the number u
5 + u means 5 more than the number u
Why it happens: Two expressions are equal only if they give the same value for every value of the letter. Here they agree only at u = 1.25, and differ everywhere else — so they are not equal expressions.
Q12.
Fill the blanks below by replacing the letter-numbers by numbers; an example is shown. Then compare the values that 5u and 5 + u take. (u = 11, 2, 8 and 5)
Answer
u5u5 + u
115516
2107
84013
52510
5 × 11 = 55 but 5 + 11 = 16
5 × 2 = 10 but 5 + 2 = 7
5 × 8 = 40 but 5 + 8 = 13
5 × 5 = 25 but 5 + 5 = 10

The two columns never match, so 5u ≠ 5 + u.

Q13.
Are the expressions 10y – 3 and 10(y – 3) equal? Let us compare the values that these expressions take for different values of y (y = 2, 0, 7, 10). After filling in the two diagrams, do you think the two expressions are equal?
Answer

10y – 3 means ‘3 less than 10 times y’, while 10(y – 3) means ‘10 times (3 less than y)’.

y10y – 310 (y – 3)
217–10
0–3–30
76740
109770
y = 2: 10 × 2 – 3 = 17, but 10 × (2 – 3) = 10 × (–1) = –10
y = 0: 0 – 3 = –3, but 10 × (–3) = –30
y = 7: 70 – 3 = 67, but 10 × 4 = 40
y = 10: 100 – 3 = 97, but 10 × 7 = 70

No, the two expressions are not equal.

Why it happens: Opening the bracket shows the gap clearly: 10(y – 3) = 10y – 30, which is 27 less than 10y – 3 for every y.
Q14.
Example 11: What is the sum of the numbers in the picture (unknown values are denoted by letter-numbers)? (four 3s on top, r and s, r and s, four 3s at the bottom)
Answer

Three different routes, one answer.

1. Row-wise: (4 × 3) + (r + s) + (r + s) + (4 × 3)
= 12 + 12 + 2r + 2s = 2r + 2s + 24

2. Like terms together: (8 × 3) + (r + r) + (s + s)
= 24 + 2r + 2s = 2r + 2s + 24

3. Upper half, doubled: 2 × (4 × 3 + r + s)
= 2 × (12 + r + s) = 24 + 2r + 2s = 2r + 2s + 24
Why it happens: The picture is symmetric top-to-bottom, so the third method works. All three expressions look different but simplify to the same thing — that is what makes them equal expressions.
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