NUMBER PLAY6
6.1 Numbers Tell us Things
What do the numbers in the figure below tell us?
Remember the children from the Grade 6 textbook of mathematics? Now, they call out numbers using a different rule.
What do you think these numbers mean?
The children rearrange themselves and each one says a number based on the new arrangement.
Could you figure out what these numbers convey? Observe and try to find out.
The rule is — each child calls out the number of children in front of them who are taller than them. Check if the number each child says matches this rule in both the arrangements.
Write down the number each child should say based on this rule for the arrangement shown below.
Figure it Out
1. Arrange the stick figure cutouts given at the end of the book or
draw a height arrangement such that the sequence reads:
(a) 0, 1, 1, 2, 4, 1, 5
(b) 0, 0, 0, 0, 0, 0, 0
(c) 0, 1, 2, 3, 4, 5, 6
(d) 0, 1, 0, 1, 0, 1, 0
(e) 0, 1, 1, 1, 1, 1, 1
(f) 0, 0, 0, 3, 3, 3, 3
2. For each of the statements given below, think and identify if it
is Always True, Only Sometimes True, or Never True. Share your reasoning.
(a) If a person says ‘0’, then they are the tallest in the group.
(b) If a person is the tallest, then their number is ‘0’.
(c) The first person’s number is ‘0’.
(d) If a person is not first or last in line (i.e., if they are standing
somewhere in between), then they cannot say ‘0’.
(e) The person who calls out the largest number is the shortest.
(f) What is the largest number possible in a group of 8 people?
6.2 Picking Parity
Kishor has some number cards and is working on a puzzle: There are 5 boxes, and each box should contain exactly 1 number card. The numbers in the boxes should sum to 30. Can you help him find a way to do it?
++++= 30
Can you figure out which 5 cards add to 30? Is it possible? There are many ways of choosing 5 cards from this collection. Is there a way to find a solution without checking all possibilities? Let us find out.
Add a few even numbers together. What kind of number do you get? Does it matter how many numbers are added?
Any even number can be arranged in pairs without any leftovers. Some even numbers are shown here, arranged in pairs.
As we see in the figure, adding any number of even numberswill result in a number which can still be arranged in pairs without any leftovers. In other words, the sum will always be an even number.
Now, add a few odd numbers together. What kind of number do you get? Does it matter how many odd numbers are added?
Odd numbers can not be arranged in pairs. An odd number is one more than a collection of pairs. Some odd numbers are shown below:
Can we also think of an odd number as one less than a collection of pairs?This figure shows that the sum of two odd numbers must always be even! This along with the other figures here are more examples of a proof!
We can see that two odd numbers added together can always be arranged in pairs.
What about adding 3 odd numbers? Can the resulting sum be arranged in pairs? No.
Explore what happens to the sum of (a) 4 odd numbers, (b) 5 odd numbers, and (c) 6 odd numbers.
Let us go back to the puzzle Kishor was trying to solve. There are 5 empty boxes. That means he has an odd number of boxes. All the number cards contain odd numbers.They should add to 30, which is an even number. Since, adding any 5 odd numbers will never result in an even number, Kishor cannot arrange these cards in the boxes to add up to 30.
Two siblings, Martin and Maria, were born exactly one year apart. Today they are celebrating their birthday. Maria exclaims that the sum of their ages is 112. Is this possible? Why or why not?
As they were born one year apart, their ages will be (two) consecutive numbers. Can their ages be 51 and 52? 51 + 52 = 103. Try some other consecutive numbers and see if their sum is 112.The counting numbers 1, 2, 3, 4, 5, ... alternate between even and odd numbers. In any two consecutive numbers, one will always be even and the other will always be odd!What would be the resulting sum of an even number and an odd number? We can see that their sum can’t be arranged in pairs and thus will be an odd number.
Since 112 is an even number, and Martin’s and Maria’s ages are consecutive numbers, they cannot add up to 112.We use the word parity to denote the property of being even or odd. For instance, the parity of the sum of any two consecutive numbers is odd. Similarly, the parity of the sum of any two odd numbers is even.
Figure it Out
1. Using your understanding of the pictorial representation of odd and even numbers, find out the parity of the following sums:
(a) Sum of 2 even numbers and 2 odd numbers (e.g., even + even + odd + odd)
(b) Sum of 2 odd numbers and 3 even numbers
(c) Sum of 5 even numbers
(d) Sum of 8 odd numbers
2. Lakpa has an odd number of ₹1 coins, an odd number of ₹5 coins and an even number of ₹10 coins in his piggy bank. He calculated the total and got ₹205. Did he make a mistake? If he did, explain why. If he didn’t, how many coins of each type could he have?
3. We know that:
(a) even + even = even
(b) odd + odd = even
(c) even + odd = odd
Similarly, find out the parity for the scenarios below:
(d) even – even = ___________________
(e) odd – odd = ___________________
(f) even – odd = ___________________
(g) odd – even = ___________________
Small Squares in Grids
In a 3 × 3 grid, there are 9 small squares, which is an odd number. Meanwhile, in a 3 × 4 grid, there are 12 small squares, which is an even number.
Given the dimensions of a grid, can you tell the parity of the number of small squares without calculating the product?
Find the parity of the number of small squares in these grids:
(a) 27 × 13
(b) 42 × 78
(c) 135 × 654
Parity of Expressions
Consider the algebraic expression: 3n + 4. For different values of n, the expression has different parity:
nValue of 3n + 4Parity of the Value
313odd
828even
1034even
Come up with an expression that always has even parity.
Some examples are: 100p and 48w – 2. Try to find more.
Come up with expressions that always have odd parity.
Come up with other expressions, like 3n + 4, which could have either odd or even parity.
The expression 6k + 2 evaluates to 8, 14, 20,... (for k = 1, 2, 3,...) — many even numbers are missing.
Are there expressions using which we can list all the even numbers?
Hint: All even numbers have a factor 2.
Are there expressions using which we can list all odd numbers?
We saw earlier how to express the nth term of the sequence of multiples of 4, where n is the letter-number that denotes a position in the sequence (e.g., first, twenty third, hundred and seventeenth, etc.).
What would be the nth term for multiples of 2? Or, what is the nth even number?
Let us consider odd numbers.
What is the 100th odd number?
To answer this question, consider the following question:
What is the 100th even number?
This is 2 × 100 = 200.Does this help in finding the 100th odd number? Let us compare the sequence of evens and odds term-by-term.Even Numbers: 2, 4, 6, 8, 10, 12,...Odd Numbers: 1, 3, 5, 7, 9, 11,...We see that at any position, the value at the odd number sequence is one less than that in the even number sequence. Thus, the 100th odd number is 200 – 1 = 199.
Write a formula to find the nth odd number.
Let us first describe the method that we have learnt to find the odd number at a given position:
(a) Find the even number at that position. This is 2 times the position number.
(b) Then subtract 1 from the even number.Writing this in expressions, we get
(a) 2n
(b) 2n – 1Thus, 2n is the formula that gives the nth even number, and 2n – 1 is the formula that gives the nth odd number.
6.3 Some Explorations in Grids
Observe this 3 × 3 grid. It is filled following a simple rule — use numbers from 1 – 9 without repeating any of them. There are circled numbers outside the grid.
475
612
398
Are you able to see what the circled numbers represent?
151713
The numbers in the yellow circles are the sums of the corresponding rows and columns.Fill the grids below based on the rule mentioned above:
12924
171612
Make a couple of questions like this on your own and challenge your peers.
Try solving the problem below.
You might have realised that it is not possible to find a solution for this grid. Why is this the case?
The smallest sum possible is 6 = 1 + 2 + 3. The largest sum possible is 24 = 9 + 8 + 7. Clearly, any number in a circle cannot be less than 6 or greater than 24. The grid has sums 5 and 26. Therefore, this is impossible!In the earlier grids which we solved, Kishor noticed that the sum of all the numbers in the circles was always 90. Also, Vidya observed that the sum of the circled numbers for all three rows, or for all three columns, was always 45. Check if this is true in the previous grids you have solved.
26119
The 3 row sums added together gives 45! So does adding the column sums.
Why should the row sums and column sums always add to 45?
From this grid, we can see that all the row sums added together will be the same as the sum of the numbers 1 – 9. This can be seen for column sums as well. The sum of the numbers 1 – 9 is
475
4+7+5
612
6+1+2
3+9+8
398
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 45.
A square grid of numbers is called a magic square if each row, each column and each diagonal, add up to the same number. This number is called the magic sum. Diagonals are shown in the picture. Trying to create a magic square by randomly filling the grid with numbers may be difÏcult! This is because there are a large number of ways of filling a 3 × 3 grid using the numbers 1 – 9 without repetition. In fact, it can be found that there are exactly 3,62,880 such ways. Surprisingly, the number of ways to fill in the grid can be found without listing all of them. We will see in later years how to do this.Instead, we should proceed systematically to make a magic square. For this, let us ask ourselves some questions.
4+6+35+2+8
7+1+9
1. What can the magic sum be? Can it be any number?
Let us focus, for the moment, only on the row sums. We have seen that in a 3 × 3 grid with numbers 1 – 9, the total of row sums will always be 45. Since in a magic square the row sums are all equal, and they add up to 45, they have to be 15 each. Thus, we have the following observation.Observation 1: In a magic square made using the numbers 1 – 9, the magic sum must be 15.
2. What are the possible numbers that could occur at the centre of a magic square?Let us consider the possibilities one by one. Can the central number be 9? If yes, then 8 must come in one of the other squares. For example,In this, we must have 8 + 9 + other number = 15.But this is not possible! The same issue will occur no matter where we place 8.So, 9 cannot be at the centre. Can the central number be 1?If yes, then 2 should come in one of the other squares. Here, we must have 2 + 1 + other number = 15.But this is not possible because we are only using the numbers 1 – 9. The same issue will occur no matter where we place 1.So, 1 cannot be at the centre, either.
Using such reasoning, find out which other numbers 1 – 9 cannot occur at the centre.
This exploration will lead us to the following interesting observation.Observation 2: The number occurring at the centre of a magic square, filled using 1 – 9, must be 5.Let us now see where the smallest number 1 and the largest number 9 should come in a magic square. Our second observation tells us that they will have to come in one of the boundary positions. Let us classify these positions into two categories:
Can 1 occur in a corner position? For example,can it be placed as follows?
If yes, then there should exist three ways of adding 1 with two other numbers to give 15. We have 1 + 5 + 9 = 1 + 6 + 8 = 15. Is any other combination possible?
1515
Similarly, can 9 can be placed in a corner position?
Observation 3: The numbers 1 and 9 cannot occur in any corner, so they should occur in one of the middle positions.
Can you find the other possible positions for 1 and 9?
159
Now, we have one full row or column of the magic square!Try completing it! [Hint: First fill the row or columns containing 1 and 9]
Figure it Out
1. How many different magic squares can be made using the numbers 1 – 9?
Math Talk
2. Create a magic square using the numbers 2 – 10. What strategy would you use for this? Compare it with the magic squares made using 1 – 9.
3. Take a magic square, and
(a) increase each number by 1
(b) double each numberIn each case, is the resulting grid also a magic square? How do the magic sums change in each case?
4. What other operations can be performed on a magic square to yield another magic square?
Math Talk
5. Discuss ways of creating a magic square using any set of 9 consecutive numbers (like 2 – 10, 3 – 11, 9 – 17, etc.).
Generalising a 3 × 3 Magic Square
We can describe how the numbers within the magic square are related to each other, i.e., the structure of the magic square.
Choose any magic square that you have made so farusing consecutive numbers. If m is the letter-number of the number in the centre, express how other numbers are related to m, how much more or less than m.
[Hint: Remember, how we described a 2 × 2 grid of a calendar month in the Algebraic Expressions chapter].
Math
Once the generalised form is obtained, share your observations with the class.
Talk
Figure it Out
1. Using this generalised form, find a magic square if the centre
number is 25.
2. What is the expression obtained by adding the 3 terms of any row,
column or diagonal?
3. Write the result obtained by—
(a) adding 1 to every term in the generalised form.
(b) doubling every term in the generalised form
4. Create a magic square whose magic sum is 60.
5. Is it possible to get a magic square by filling nine non-consecutive numbers?
TryThis
The First-ever 4 × 4 Magic Square
The first ever recorded 4 × 4 magic square is found in a 10th century inscription at the Pārśhvanath Jain temple in Khajuraho, India, and is known as the Chautīsā Yantra.
712114
213811
163105
96154
The first ever recorded 4 × 4 magic square, the Chautīsā Yantra, at Khajuraho, India
Chau̐ tīs means 34. Why do you think they called it the Chautīsā Yantra?Every row, column and diagonal in this magic square adds up to 34.Can you find other patterns of four numbers in the square that add up to 34?
Magic Squares in History and Culture
The first magic square ever recorded, the Lo Shu Square, dates back over 2000 years to ancient China. The legend tells of a catastrophic flood on the Lo River, during which the gods sent a turtle to save the people. The turtle carried a 3 × 3 grid on its back, with the numbers 1 to 9 arranged in a magical pattern.Magic squares were studied in different parts of the world at different points of time including India, Japan, Central Asia, and Europe.Indian mathematicians have worked extensively on magic squares, describing general methods of constructing them. The work of Indian mathematicians was not just limited to 3 × 3 and 4 × 4 grids, which we considered above, but also extended to 5 × 5 and other larger square grids. We shall learn more about these in later grades.The occurrence of magic squares is not limited to scholarly mathematical works. They are found in many places in India. The picture to the right is of a 3 × 3 magic square found on a pillar in a temple in Palani, Tamil Nadu. The temple dates back to the 8th century CE.3 × 3 magic squares can also be found in homes and shops in India. The Navagraha Yantra is one such example shown below.
276
951
438
Notice that a different magic sum is associated with each graha. A picture of a Kubera Yantra is shown below:
272025
222426
232821
6.4 Nature’s Favourite Sequence: The Virahāṅka–Fibonacci Numbers!
The sequence 1, 2, 3, 5, 8, 13, 21, 34, . . . (Virahāṅka–Fibonacci Numbers) is one of the most celebrated sequences in all of mathematics — it occurs throughout the world of Art, Science, and Mathematics. Even though these numbers are found very frequently in Science, it is remarkable that these numbers were first discovered in the context of Art (specifically, poetry)! The Virahāṅka–Fibonacci Numbers thus provide a beautiful illustration of the close links between Art, Science, and Mathematics.
Discovery of the Virahāṅka Numbers
The Virahāṅka numbers first came up thousands of years ago in the works of Sanskrit and Prakrit linguists in their study of poetry!In the poetry of many Indian languages, including, Prakrit, Sanskrit, Marathi, Malayalam, Tamil, and Telugu, each syllable is classified as either long or short. A long syllable is pronounced for a longer duration than a short syllable — in fact, for exactly twice as long. When singing such a poem, a short syllable lasts one beat of time, and a long syllable lasts two beats of time.This leads to numerous mathematical questions, which the ancient poets in these languages considered extensively. A number of important mathematical discoveries were made in the process of asking and answering these questions about poetry. One of these particularly important questions was the following.How many rhythms are there with 8 beats consisting of short syllables (1 beat) and long syllables (2 beats)? That is, in how many ways can one
fill 8 beats with short and long syllables, where a short syllable takes one beat of time and a long syllable takes two beats of time.Here are some possibilities:
long long long longshort short short short short short short shortshort long long short longlong long short short long
. . .Can you find others?Phrased more mathematically: In how many different ways can one write a number, say 8, as a sum of 1’s and 2’s?For example, we have:
8 = 2 + 2 + 2 + 2, 8 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1, 8 = 1 + 2 + 2 + 1 + 2, 8 = 2 + 2 + 1 + 1 + 2, etc.Do you see other ways?Here are all the ways of writing each of the numbers 1, 2, 3, and 4, as the sum of 1’s and 2’s.
Different WaysNumber of Ways
n = 111
n = 21 + 122
n = 31 + 1 + 11 + 22 + 13
1 + 1 + 1 + 11 + 1 + 21 + 2 + 12 + 1 + 12 + 2
n = 4
Try writing the number 5 as a sum of 1s and 2s in all possible ways in your notebook! How many ways did you find? (You should find 8 different ways!) Can you figure out the answer without listing down all the possibilities? Can you try it for n = 8? Here is a systematic way to write down all rhythms of short and long syllables having 5 beats. Write a ‘1+’ in front of all rhythms having 4 beats, and then a ‘2+’ in front of all rhythms having 3 beats. This gives us all the rhythms having 5 beats:
n = 51 + 1 + 1 + 1 + 11 + 1 + 1 + 21 + 1 + 2 + 11 + 2 + 1 + 11 + 2 + 2
2 + 1 + 1 + 12 + 1 + 22 + 2 + 1
Thus, there are 8 rhythms having 5 beats!The reason this method works is that every 5-beat rhythm must begin with either a ‘1+’ or a ‘2+’. If it begins with a ‘1+’, then the remaining numbers must give a 4-beat rhythm, and we can write all those down. If it begins with a 2+, then the remaining number must give a 3-beat rhythm, and we can write all those down. Therefore, the number of 5-beat rhythms is the number of 4-beat rhythms, plus the number of 3-beat rhythms.How many 6-beat rhythms are there? By the same reasoning, it will be the number of 5-beat rhythms plus the number of 4-beat rhythms, i.e., 8 + 5 = 13. Thus, there are 13 rhythms having 6 beats.
Use the systematic method to write down all 6-beat rhythms, i.e., write 6 as the sum of 1’s and 2’s in all possible ways. Did you get 13 ways?
This beautiful method for counting all the rhythms of short syllables and long syllables having any given number of beats was first given by the great Prakrit scholar Virahāṅka around the year 700 CE. He gave his method in the form of a Prakrit poem! For this reason, the sequence 1, 2, 3, 5, 8, 13, 21, 34, . . . is known as the Virahāṅka sequence, and the numbers in the sequence are known as the Virahāṅka numbers. Virahāṅka was the first known person in history to explicitly consider these important numbers and write down the rule for their formation.Other scholars in India also considered these numbers in the same poetic context. Virahāṅka was inspired by earlier work of the legendary Sanskrit scholar Piṅgala, who lived around 300 BCE. After Virahāṅka, these numbers were also written about by Gopala (c. 1135 CE) and then by Hemachandra (c. 1150 CE).In the West, these numbers have been known as the Fibonacci numbers, after the Italian mathematician who wrote about them in the year 1202 CE — about 500 years after Virahāṅka. As we can see, Fibonacci was not first, nor the second, not even the third person to write about these numbers! Sometimes the term “Virahāṅka–Fibonacci numbers” is used so that everyone understands what is being referred to.So, how many rhythms of short and long syllables are there having 8 beats? We simply take the 8th element of the Virahāṅka sequence:1, 2, 3, 5, 8, 13, 21, 34, 55, ... Thus, there are 34 rhythms having 8 beats.
Write the next number in the sequence, after 55.We have seen that the next number in the sequence is given by adding the two previous numbers. Check that this holds true for the numbers given above. The next number is 34 + 55 = 89.
Write the next 3 numbers in the sequence:
1, 2, 3, 5, 8, 13, 21, 34 , 55, 89, ____, ____, ____, …
If you have to write one more number in the sequence above, can you tell whether it will be an odd number or an even number (without adding the two previous numbers)?
What is the parity of each number in the sequence? Do you notice any pattern in the sequence of parities?
Today, the Virahāṅka–Fibonacci numbers form the basis of many mathematical and artistic theories, from poetry to drumming, to visual arts and architecture, to science. Perhaps the most stunning occurrences of these numbers are in nature. For example, the number of petals on a daisy is generally a Virahāṅka number.How many petals do you see on each of these flowers?
A daisy with 13 petals
A daisy with 21 petals
A daisy with 34 petals
There are many other remarkable mathematical properties of the Virahāṅka–Fibonacci numbers that we will see later, in mathematics as well as in other subjects. These numbers truly exemplify the close connections between Art, Science, and Mathematics.
6.5 Digits in Disguise
You have done arithmetic operations with numbers. How about doing the same with letters?
In the calculations below, digits are replaced by letters. Each letter stands for a particular digit (0 – 9). You have to figure out which digit each letter stands for.
+ T
UT
Here, we have a one-digit number that, when added to itself twice, gives a 2-digit sum. The units digit of the sum is the same as the single digit being added.
What could U and T be? Can T be 2? Can it be 3?
K2
Once you explore, you will see that T = 5 and UT = 15.Let us look at one more example shown on the right. Here K2 means that the number is a 2-digit number having the digit ‘2’ in the units place and ‘K’ in the tens place. K2 is added to itself to give a 3-digit sum HMM. What digit should the letter M correspond to? Both the tens place and the units place of the sum have the same digit.
+ K2
HMM
What about H? Can it be 2? Can it be 3?
These types of questions can be interesting and fun to solve! Here are some more questions like this for you to try out. Find out what each letter stands for.Share how you thought about each question with your classmates; you may find some new approaches.
YYB5KPC1
+ Z+ 3D+ KP+ C
ZOOED5PRR1FF
These types of questions are called ‘cryptarithms’ or ‘alphametics’.
Figure it Out
1. A light bulb is ON. Dorjee toggles its switch 77 times. Will the bulb be on or off? Why?
2. Liswini has a large old encyclopaedia. When she opened it, several
loose pages fell out of it. She counted 50 sheets in total, each printed on both sides. Can the sum of the page numbers of the loose sheets be 6000? Why or why not?
3. Here is a 2 × 3 grid. For each row and column,
the parity of the sum is written in the circle; ‘e’ for even and ‘o’ for odd. Fill the 6 boxes with 3 odd numbers (‘o’) and 3 even numbers (‘e’) to satisfy the parity of the row and column sums.
oee
4. Make a 3 × 3 magic square with 0 as the magic
sum. All numbers can not be zero. Use negative numbers, as needed.
5. Fill in the following blanks with ‘odd’ or ‘even’:
(a) Sum of an odd number of even numbers is ______
(b) Sum of an even number of odd numbers is ______
(c) Sum of an even number of even numbers is ______
(d) Sum of an odd number of odd numbers is ______
6. What is the parity of the sum of the numbers from 1 to 100?
7. Two consecutive numbers in the Virahāṅka sequence are 987 and
1597. What are the next 2 numbers in the sequence? What are the previous 2 numbers in the sequence?
8. Angaan wants to climb an 8-step staircase. His playful rule is that
he can take either 1 step or 2 steps at a time. For example, one of his paths is 1, 2, 2, 1, 2. In how many different ways can he reach the top?
9. What is the parity of the 20th term of the Virahāṅka sequence?
10. Identify the statements that are true.
(a) The expression 4m – 1 always gives odd numbers.
(b) All even numbers can be expressed as 6j – 4.
(c) Both expressions 2p + 1 and 2q – 1 describe all odd numbers.
(d) The expression 2f + 3 gives both even and odd numbers.
11. Solve this cryptarithm:
UT
+ TA
TAT
SUMMARY
In this chapter, we have explored the following:• In the first activity, we saw how to represent information about how a sequence of numbers (e.g., height measures) is arranged without knowing the actual numbers.• We learnt the notion of parity — numbers that can be arranged in pairs (even numbers) and numbers that cannot be arranged in pairs (odd numbers).• We learnt how to determine the parity of sums and products.• While exploring sums in grids, we could determine whether filling a grid is impossible by looking at the row and column sums. We extended this to construct magic squares.• We saw how Virahāṅka numbers were first discovered in history through the Arts. The Virahāṅka sequence is 1, 2, 3, 5, 8, 13, 21, 34, 55, ... • We became math-detectives through cryptarithms, where digits are replaced by letters.
I just heard that 14,70,369 people got married last year.
Wait, shouldn’t it be an even number?
CHAPTER – 6 Number Play
Page No- 128
Write down the number each child should say based on this rule for the
arrangement shown below.
The rule is:
Each child calls out the number of children standing in front of them who are taller than they are. Let’s assign the numbers from left to right for the 7 children:
Child 1: From left → 0 Child 2: From left → 0 Child 3: From left → 1 Child 4: From left → 0 Child 5: From left → 3 Child 6: From left → 0 Child 7: From left → 3
Figure it out
1. Arrange the stick figure cutouts given at the end of the book or draw a height arrangement such that the sequence reads: (a) 0, 1, 1, 2, 4, 1, 5 (b) 0, 0, 0, 0, 0, 0, 0 (c) 0, 1, 2, 3, 4, 5, 6 (d) 0, 1, 0, 1, 0, 1, 0 (e) 0, 1, 1, 1, 1, 1, 1 (f) 0, 0, 0, 3, 3, 3, 3
Ans:
(a) From the cutouts at the back of the book we have → F, C, B, G, A, D, E
May also like to draw this way —
Try for other subparts
2. For each of the statements given below, think and identify if it is Always
True, Only Sometimes True, or Never True. Share your reasoning.
(a) If a person says ‘0’, then they are the tallest in the group.
(b) If a person is the tallest, then their number is ‘0’.
(c) The first person’s number is ‘0’.
(d) If a person is not first or last in line (i.e., if they are standing
somewhere in between), then they cannot say ‘0’.
(e) The person who calls out the largest number is the shortest.
(f) What is the largest number possible in a group of 8 people? Ans:
(a) Only sometimes true
(b) Always true
(c) Always true
(d) Only sometimes true
(e) Only sometimes true
(f) The largest possible number in a group of 8 people is 7
Page No- 131
Figure it out
1. Using your understanding of the pictorial representation of odd and even
numbers, find out the parity of the following sums: (a) Sum of 2 even numbers and 2 odd numbers (e.g., even + even + odd +
odd)
(b) Sum of 2 odd numbers and 3 even numbers
(c) Sum of 5 even numbers
(d) Sum of 8 odd numbers
Ans:
(a) Even number (b) Even number (c) Even number (d) Even number
2. Lakpa has an odd number of ₹1 coins, an odd number of ₹5 coins and an
even number of ₹10 coins in his piggy bank. He calculated the total and got ₹205. Did he make a mistake? If he did, explain why. If he didn’t, how many coins of each type could he have? Ans:
Lakpa must have made a mistake! The total can never be ₹205 with the given coin counts. 3. We know that:
(a) even + even = even
(b) odd + odd = even
(c) even + odd = odd
Similarly, find out the parity for the scenarios below:
(d) even – even = _____
(e) odd – odd = _____
(f) even – odd = _____
(g) odd – even = _____
Ans:
(d) Even (e) Even (f) Odd (g) Odd
Given the dimensions of a grid, can you tell the parity of the number of
small squares without calculating the product?
Ans:
The parity of the number of small squares in a grid (with m rows and n columns) is:
(i) Even, if at least one of the numbers (either m or n) is even. (ii) Odd, if both numbers (m and n) are odd. (iii) Even, if both numbers (m and n) are even.
Page No- 132
Find the parity of the number of small squares in these grids:
(a) 27 × 13 (b) 42 × 78 (c) 135 × 654
Ans:
(a) Odd (b) Even (c) Even
Come up with an expression that always has odd parity. Ans:
Some such expressions are 2m + 1, 8a + 3; 4n + 3, 6n + 5 etc.
Come up with other expressions, like 3n + 4, which could have either odd
or even parity. Ans:
(i) If n is odd, then 3n + 4 is odd then some expressions of odd parity would be—
5n + 2, 9n + 4 etc. Some expressions of even parity — 2n + 4, 4n + 6 etc. (ii) If n is even, then 3n + 4 is even then all expression will be even parity —
(5n – 2), n + 4 etc.
Are there expressions using which we can list all odd numbers? Ans: 2n-1 is the expression that can list all odd numbers.
What would be the nth term for multiples of 2? Or, what is the nth even
number? Ans: 2n
Fill the grids below based on the rule mentioned above:
Ans:
Try to find out other possible ways.
Page No- 136
Figure it out 1. How many different magic squares can be made using the numbers 1 – 9? Ans: There is exactly one unique magic square with numbers 1 – 9, if we ignore
rotations and reflections.
8 1 6
3 5 7
4 9 2
2. Create a magic square using numbers 2 – 10. What strategy would you use
for this? Compare it with the magic squares made using 1 – 9. Ans: We will add 1 to every number in the magic square in Q.1
9 2 7
4 6 8
5 10 3
3. Take a magic square, and
(a) Increase each number by 1 (b) Double each number In each case, is the resulting grid also a magic square? How do the magic sums change in each case?
Ans: Consider the magic square.
8 1 6
3 5 7
4 9 2
(a) After increasing each number by 1:
9 2 7
4 6 8
5 10 3
This is still a magic square.
(b) After Doubling each number:
16 2 12
6 10 14
8 18 4
This is still a magic square In case (a), magic sum is increased by 3 times that constant. (i.e., 1) In case (b), magic sum is multiplied by that constant. (i.e., 2)
4. What other operations can be performed on a magic square to yield
another magic square? Ans:
Operations like Addition, subtraction, multiplication and division can be performed on a magic square to yield another magic square.
5. Discuss ways of creating a magic square using any set of 9 consecutive
numbers (like 2 – 10, 3 – 11, 9 – 17, etc.). Ans:
Magic square with numbers 1 – 9:
8 1 6
3 5 7
4 9 2
Magic square with numbers 2 – 10 can be created by adding 1 to each number of the magic square 1 – 9.
9 2 7
4 6 8
5 10 3
Magic square with numbers 3 – 11 can be created by adding 2 to each number of the magic square 1 – 9. Magic square with numbers 9 – 17 can be created by adding 8 to each number of the magic square 1 – 9.
Choose any magic square that you have made so far using consecutive
numbers. If m is the letter-number of the number in the centre, express how other numbers are related to m, how much more or less than m. [Hint: Remember, how we described a 2 × 2 grid of a calendar month in the Algebraic Expressions chapter]. Ans: Taking ‘m’ as the letter-number of the number in the centre and expressing
other numbers in relation to ‘m’.
m + 3 m – 4 m + 1
m – 2 m m + 2
m – 1 m + 4 m – 3
Page No- 137
Figure it out 1. Using this generalised form, find a magic square if the centre number is
25. Ans:
28 21 26
23 25 27
24 29 22
2. What is the expression obtained by adding the 3 terms of any row,
column, or diagonal? Ans: The expression obtained = 3 × m
where m is the letter - number representing the number in the centre.
3. Write the result obtained by
(a) Adding 1 to every term in the generalised form. (b) Doubling every term in the generalised form. Ans:
(a)
m + 4 m – 3 m + 2
m – 1 m + 1 m + 3
m m + 5 m – 2
(b)
2m + 6 2m – 8 2m + 2
2m – 4 2m 2m + 4
2m – 2 2m + 8 2m – 6
4. Create a magic square whose magic sum is 60. Ans:
23 16 21
18 20 22
19 24 17
5. Is it possible to get a magic square by filling nine non-consecutive
numbers? Ans:
Yes, it is possible.
24 3 18
9 15 21
12 27 6
Try some more.
Page No- 142
Write the next 3 numbers in the sequence:
1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ____, ____, ____, … If you have to write one more number in the sequence above, can you tell whether it will be an odd number or an even number (without adding the two previous numbers)?
Ans: 55 + 89 = 144, 89 + 144 = 233, 144 + 233 = 3779
The next number will be an even number.
What is the parity of each number in the sequence? Do you notice any
pattern in the sequence of parities?
The parity patterns — Sequence: 1(O), 2(E), 3(O), 5(O), 8(E), 13(O), 21(O), 34(E), … The pattern is: Odd, Even, Odd, Odd, Even, Odd, Odd, Even…. The group odd, even, odd repeats.
3rd term = 1st term + 2nd term = O + E = O;
4th term = 2nd term + 3rd term = E + O = O;
5th term = 3rd term + 4th term = O + O = E…
Page No- 143-44
Figure it out 1. A light bulb is ON. Dorjee toggles its switch 77 times. Will the bulb be on or
off? Why? Ans. The bulb will be OFF.
2. Liswini has a large old encyclopaedia. When she opened it, several loose
pages fell out of it. She counted 50 sheets in total, each printed on both sides. Can the sum of the page numbers of the loose sheets be 6000? Why or why not? Ans. Each sheet has two pages, one with an even number and the other with an odd
number. Since there are 50 sheets, so there will be fifty pages with an even number and 50 pages with an odd number The sum of the even numbers is even. The sum of the odd numbers taken even number of times is also even. Thus, 6000 being even, it is possible that sum of all the page numbers of the loose sheets could be 6000.
3. Here is a 2 × 3 grid. For each row and column, the parity of the sum is
written in the circle; ‘e’ for even and ‘o’ for odd. Fill the 6 boxes with 3 odd numbers (‘o’) and 3 even numbers (‘e’) to satisfy the parity of the row and column sums.
Ans: One of the ways is –
Try more combinations.
4. Make a 3 × 3 magic square with 0 as the magic sum. All numbers cannot
be zero. Use negative numbers, as needed. Ans: One of the such magic squares is –
3 – 4 1
– 2 0 2
– 1 4 – 3
5. Fill in the following blanks with ‘odd’ or ‘even’:
(a) Sum of an odd number of even numbers is ______ (b) Sum of an even number of odd numbers is ______ (c) Sum of an even number of even numbers is ______ (d) Sum of an odd number of odd numbers is ______ Ans:
(a) Even. (b) Even.
(c) Even. (d) Odd.
6. What is the parity of the sum of numbers from 1 to 100? Ans: The parity is even. [Hint– Add numbers from 1 to 100.]
7. Two consecutive numbers in the Virahanka sequence are 987 and 1597.
What are the next 2 numbers in the sequence? What are the previous 2 numbers in the sequence? Ans:
The next two numbers are: 987 + 1597 = 2584 1597 + 2584 = 4181 The previous two numbers are: 1597 – 987 = 610 987 – 610 = 377 The sequence is …, 377, 610, 987, 1597, 2584, 4181, …
8. Angaan wants to climb an 8 - step staircase. His playful rule is that he can
take either 1 step or 2 steps at a time. For example, one of his paths is 1, 2, 2, 1, 2. In how many different ways can he reach the top? Ans:
Different Ways Number of ways
1, 1, 1, 1, 1, 1, 1, 1 1
1, 1, 1, 1, 1, 1, 2 1, 1, 1, 1, 1, 2, 1
. . .
1, 1, 1, 1, 2, 2 1, 1, 1, 2, 1, 2
. . .
1, 1, 2, 2, 2 1, 2, 2, 2, 1
. . .
2, 2, 2, 2 1
So, the total ways in which Angaan reaches the top = 1 + 7 + 15 + 10 + 1 = 34 ways.
9. What is the parity of the 20th term of the Virahanka sequence? Ans:
Consider the Virahanka sequence given below: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, …. The pattern of odd/even in Virahanka numbers is: O, E, O, O, E, O … So the 20th term of the Virahanka sequence is even. 10. Identify the true statements.
(a) The expression 4m – 1 always gives odd numbers. (b) All even numbers can be expressed as 6j – 4. (c) Both expressions 2p + 1 and 2q – 1 describe all odd numbers. (d) The expression 2f + 3 gives both even and odd numbers.
Ans:
(a) True (b) False (c) False (d) False 11. Solve this cryptarithm:
Ans:
U = 9, T = 1 and A = 0.