Q1.
A water tank is filled from a tap. If the tap is open for 1 hour, 7⁄10 of the tank gets filled. How much of the tank is filled if the tap is open for (a) 1⁄3 hour ____ (b) 2⁄3 hour ____ (c) 3⁄4 hour ____ (d) 7⁄10 hour ____ (e) For the tank to be full, how long should the tap be running?
Answer
Each part is (time) × 7⁄10.
| Tap open for | Working | Part of tank filled |
|---|---|---|
| (a) 1/3 hour | 1/3 × 7/10 | 7/30 |
| (b) 2/3 hour | 2/3 × 7/10 = 14/30 | 7/15 |
| (c) 3/4 hour | 3/4 × 7/10 | 21/40 |
| (d) 7/10 hour | 7/10 × 7/10 | 49/100 |
(e) The tank is full when the filled part is 1.
Time = 1 ÷ 7/10
= 1 × 10/7
= 10/7 hours = 1 3/7 hours ≈ 1 hour 26 minutes
= 1 × 10/7
= 10/7 hours = 1 3/7 hours ≈ 1 hour 26 minutes
Why it happens: in 7⁄10 of an hour only 49⁄100 of the tank fills — less than half — because you are taking a part of a part.