Q1.
Make a general statement about the HCF for the following pairs of numbers. You could consider examples before coming up with general statements. Look for possible explanations of why they hold. (a) Two consecutive even numbers (b) Two consecutive odd numbers (c) Two even numbers (d) Two consecutive numbers (e) Two co-prime numbers. Share your observations with the class.
Answer
Try examples first, then state the rule.
| Examples | HCF | General statement | |
|---|---|---|---|
| (a) consecutive even | 6, 8 → 2 14, 16 → 2 30, 32 → 2 | always 2 | The HCF of two consecutive even numbers is 2. |
| (b) consecutive odd | 7, 9 → 1 15, 17 → 1 21, 23 → 1 | always 1 | Two consecutive odd numbers are co-prime; their HCF is 1. |
| (c) two even | 6, 8 → 2 12, 18 → 6 20, 100 → 20 | an even number | The HCF of two even numbers is always even (at least 2), but it can be anything even. |
| (d) consecutive | 8, 9 → 1 20, 21 → 1 99, 100 → 1 | always 1 | Two consecutive numbers are always co-prime. |
| (e) co-prime | 4, 9 → 1 25, 42 → 1 | always 1 | The HCF of two co-prime numbers is 1, by definition. |
Why they hold:
- (d) Write them as n and n + 1. A common factor must divide the difference, which is 1. The only number that divides 1 is 1 itself.
- (a) Write them as 2n and 2n + 2 = 2(n + 1). Both contain a 2, so 2 is common. Beyond that, the HCF of n and n + 1 is 1 by (d), so nothing more can be shared. HCF = 2 × 1 = 2.
- (b) Their difference is 2, so any common factor divides 2 — it is 1 or 2. But both numbers are odd, so 2 cannot divide them. Only 1 is left.
- (c) Both are multiples of 2, so 2 is a common factor and the HCF is at least 2. How much more they share depends on the numbers, so no fixed value can be promised.
- (e) "Co-prime" means "no common prime factor". With no shared prime, the largest common subpart is empty, which is 1.