NCERT Solutions for Class 7th Maths Chapter 3 Try This — Efficient Procedures

Book page 62 Updated on2026-09-19

Q1.
Guna says “I found a better way to factorise to find HCF/LCM. This is faster than what was taught in class! For the numbers 300 and 150, I can first directly divide both numbers by 50. The HCF will be 50 × 3. The LCM will be 50 × 3 × 2 × 1”. Anshu also tried to remove the bigger common factors. “For 630 and 770, I will divide both numbers by 10 first. Now, I can divide them by 7. The HCF will be 10 × 7 = 70. The LCM will be 10 × 7 × 9 × 11 = 6930”. Can you see why this works?
Answer

It works because a step of the ladder never has to be a prime — any common factor will do.

Guna, on 300 and 150
50 | 300, 150 → 6, 3
 3 |   6,   3 → 2, 1
HCF = 50 × 3 = 150
LCM = 50 × 3 × 2 × 1 = 300
Anshu, on 630 and 770
10 | 630, 770 → 63, 77
 7 |  63,  77 → 9, 11
HCF = 10 × 7 = 70
LCM = 10 × 7 × 9 × 11 = 6930

Both answers agree exactly with the slower prime-by-prime ladders on page 61.

Why it happens: dividing both numbers by 50 in one go is the same as dividing by 2, then by 5, then by 5 again — the three rows are merged into one. The left column still multiplies to the same thing, because 50 = 2 × 5 × 5. Nothing is skipped; the primes are only collected in bigger bundles. The one condition is that the divisor must be a common factor of both numbers, and that you keep going until the leftovers share nothing.
Tip: the shortcut is only safe if you finish the job. If Guna had stopped after dividing by 50, he would have got 50 as the HCF instead of 150 — because 6 and 3 still share a 3.
Q2.
You can try this method for these pairs of numbers. (a) 90 and 150 (b) 84 and 132
Answer

(a) 90 and 150 — spot the common factor 30 straight away.

30 | 90, 150 → 3, 5
3 and 5 share nothing — stop
HCF = 30
LCM = 30 × 3 × 5 = 450

Check with primes: 90 = 2 × 3 × 3 × 5 and 150 = 2 × 3 × 5 × 5. HCF = 2 × 3 × 5 = 30 ✓, LCM = 2 × 3 × 3 × 5 × 5 = 450 ✓

(b) 84 and 132 — both end in an even digit and both have digit sums divisible by 3, so 12 is worth trying.

12 | 84, 132 → 7, 11
7 and 11 share nothing — stop
HCF = 12
LCM = 12 × 7 × 11 = 924

Check with primes: 84 = 2 × 2 × 3 × 7 and 132 = 2 × 2 × 3 × 11. HCF = 2 × 2 × 3 = 12 ✓, LCM = 2 × 2 × 3 × 7 × 11 = 924 ✓

Check it yourself: HCF × LCM should equal the product. (a) 30 × 450 = 13,500 = 90 × 150 ✓   (b) 12 × 924 = 11,088 = 84 × 132 ✓
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