NCERT Solutions for Class 8th Maths Chapter 4 Exploring Some Geometric Themes

Updated on 2026-09-19

About this chapter

A fractal is a self-similar shape: it contains smaller copies of itself, over and over. Ferns, trees, coastlines, lightning and the towers of the Kandariya Mahadev Temple at Khajuraho all show this. The Sierpinski Carpet keeps 8 of every 9 sub-squares at each step, so R n = 8 n squares remain, H n = (8 n − 1)⁄7 holes have appeared, and the remaining area is (8⁄9) n — shrinking towards 0. The Sierpinski Gasket keeps 3 of every 4 triangles: 3 n triangles remain, (3 n − 1)⁄2 holes have been cut, and the area left is (3⁄4) n . The Koch Snowflake replaces every side by four sides one-third as long. So it has 3 × 4 n sides of length (1⁄3) n , and a perimeter 3 × (4⁄3) n that grows without limit — an unbounded boundary around a bounded region. A net is a solid unfolded flat. A cube has 11 nets, a

  • .1 Fractals
  • Sierpinski Gasket
  • Koch Snowflake
  • .2 Visualising Solids
  • Making Solids
  • Nets of a cube
  • Nets of other solids
  • Nets of a cylinder and a cone
  • The octahedron and the dodecahedron
  • Shortest Paths on a Cube
Quick revision
IdeaRule for one stepFormula at step nWhat it tells you
Sierpinski Carpet — squares leftRn+1 = 8 RnRn = 8n1, 8, 64, 512, …
Sierpinski Carpet — holesHn+1 = Hn + RnHn = (8n − 1)⁄70, 1, 9, 73, …
Sierpinski Carpet — areaeach square shrinks to 1⁄9(8⁄9)nArea falls to 0; the fractal has no area
Sierpinski Gasket — triangles leftTn+1 = 3 TnTn = 3n1, 3, 9, 27, …
Sierpinski Gasket — holesHn+1 = Hn + TnHn = (3n − 1)⁄20, 1, 4, 13, …
Sierpinski Gasket — areaeach triangle shrinks to 1⁄4(3⁄4)nArea falls to 0
Koch Snowflake — sideseach side becomes 4 sidesSn = 3 × 4n3, 12, 48, 192, …
Koch Snowflake — perimeterlength × 4⁄3 each stepPn = 3 × (4⁄3)n3, 4, 16⁄3, … grows without bound
Prism on an n-gon—n + 2 faces, 3n edges, 2n verticesF + V − E = 2
Pyramid on an n-gon—n + 1 faces, 2n edges, n + 1 verticesF + V − E = 2
Netsunfold the solid flatcube 11, tetrahedron 2, octahedron 11, dodecahedron 43,380A sphere has no net
Shortest path on a cuboidunfold, then join by a straight linecheck every unfoldingDifferent unfoldings give different lengths
Projection of a segmentdrop a perpendicular to the planep ≤ l, with p = l only when the segment is parallel to the planeProjections shorten, never stretch
Three standard viewsproject on three perpendicular planesfront view, top view, side viewOne view alone does not fix the solid
Read the chapter
  1. .1 Fractals — In-text Questions Page 714
  2. .1 Fractals — In-text Question Page 724
  3. Sierpinski Gasket — Figure it Out Page 72
  4. Koch Snowflake — Figure it Out Page 73
  5. .2 Visualising Solids — Build it in Your Imagination Page 75–774
  6. Making Solids — In-text Questions Page 79
  7. Making Solids — In-text Questions Page 80
  8. Nets of a cube — Figure it Out Page 80–81
  9. Nets of other solids — In-text Questions Page 81
  10. Nets of a cylinder and a cone — In-text Questions Page 82
  11. The octahedron and the dodecahedron — In-text Questions Page 83
  12. Shortest Paths on a Cube — In-text Questions Page 84–85
  13. Shortest Paths on a Cube — In-text Questions Page 86–87
  14. Representation of Solids on a Plane Surface — In-text Questions Page 89–91
  15. Front view, top view and side view — Figure it Out Page 92–93
  16. Shadows — In-text Questions Page 94
  17. Views of solids built from cubes — Figure it Out Page 95–97
  18. Isometric Projections and isometric drawing — In-text Questions Page 97–100
  19. Drawing on Isometric Grids — Figure it Out Page 100–102
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