Exploring Mixtures and their Separation

Class 9 science · Exploration · Chapter 5

← Back to solutions

Think It Over

Have you ever wondered how sweet, white crystals of sugar are obtained from tall, green sugarcane plants? Or how do doctors detect diseases like malaria using just a few drops of blood? Many such everyday activities are made possible by techniques based on the fascinating science of separating mixtures.

• Why do suspended particles settle in muddy water over time but not in milk? • How is evaporation different from boiling? • Why do you see bright rays of sunlight when it passes through small gaps between the leaves of a dense tree?

You have learnt about mixtures and some simple methods to separate them. In this chapter, you will explore mixtures in greater depth, including their properties, behaviour and the various techniques used to separate them. From industrial processes like sugar production to life-saving medical tests, the separation of mixtures plays a crucial role in our daily lives.

Grade 6CuriosityChapter 9

5.1 How Can We Classify Mixtures?

You have learnt that a mixture of sugar and water has a uniform composition throughout. A well-stirred mixture of sugar and water is equally sweet in the first and the last sip. Such a mixture is called a homogeneous mixture (Fig. 5.1) or a solution. Other examples of homogeneous mixtures are vinegar (acetic acid in water), aerated drinks like soda (carbon dioxide in water), etc. A solution always remains homogeneous.

Grade 8CuriosityChapter 9

Fig 5.1

On the other hand, a stirred mixture of sand and water is not uniform. The sand particles are easily visible in the water and settle with time. Such a mixture is called a heterogeneous mixture (Fig. 5.2). Is the mixture of oil and water homogeneous or heterogeneous? Can you think of some other heterogeneous mixtures?

Activity 5.1: Let us experiment — Group activity Divide the class into three groups — A, B and C. Each group prepares a mixture in a colourless, transparent glass tumbler or a 100 mL beaker by following these steps:

1. Group A: Add one spatula of common salt to 50 mL of

Fig 5.2

water in a beaker and stir it well. Label it A. 2. Group B: Add one spatula of chalk

powder to 50 mL of water in a beaker and stir it well. Label it B.3. Group C: Add a few drops of milk to

50 mL of water in a beaker and stir it well. Label it C.4. Are the particles visible in each mixture? Record your observations. 5. Direct the light from a laser

(a)

pointer through the beakers containing the mixtures (Fig. 5.3) and observe it from the side of the beaker in a direction perpendicular to the laser beam. Record your observations. Safety first: Do not look directly into the laser beam. It can cause irreversible eye damage.

(b)

6. Predict what you would observe

in each of the beakers if you leave them undisturbed for a few minutes.

(c)

Fig. 5.3: Passing laser light through various mixtures (a) salt and water, (b) chalk powder and water, and (c) milk and water

7. Set up a filtration apparatus and filter each mixture separately. Is

there any residue left on the filter paper?8. Based on your observations, do you think these are the same types of

mixtures or are they different?These are indeed different types of mixtures. How? Let us explore further!

5.2 Solutions

You have learnt that solutions are homogeneous mixtures. You have also learnt that solutions are prepared when a solute (the substance that gets dissolved) is mixed with a solvent (the substance that dissolves the solute). In the mixture of sugar and water, sugar is the solute, and water is the solvent. In what proportion are a solute and a solvent present in a solution? Can these be expressed quantitatively?

Grade 8CuriosityChapter 9

5.2.1 Concentration of a solution

You have learnt how Oral Rehydration Solution (ORS) is prepared. We add specified amounts of salt and sugar to a fixed amount of water to prepare ORS. If we change the amount of salt or sugar added to the same volume of water, or change the volume of water for the specified amounts of salt and sugar, we will get a solution of salt and sugar in water, but that will not be ORS. In other words, we cannot freely add any amount of salt and sugar to a fixed amount of water to make ORS.

Grade 6CuriosityChapter 6

Note

Not all sugary drinks prepared at home or sold in the market are ORS.

Let us take another example. When farmers spray pesticides on their crops, they must mix the right amount of pesticide with a fixed amount of water to prepare a solution. If they do not do so, what is likely to happen? Too little pesticide may not protect crops, while too much can damage crops, soil and the environment.

Can you think of other such examples?The right proportion is always essential when preparing a solution.

Meet a Scientist

Dilip Mahalanabis, an Indian paediatrician, first developed and implemented the treatment for dehydration caused by diseases, such as diarrhoea and cholera. He formulated the ORS that has revolutionised rehydration therapy. It has saved millions of lives after the World Health Organization (WHO) popularised it worldwide.

The amount of solute dissolved in a given amount of solvent or solution is termed as the concentration of the solution.

Understanding concentration is essential not only in science laboratories but also in everyday life, whether in medicine, agriculture, food, cosmetics, or even while making a simple cup of tea!

5.2.2 How do we express concentration?

Let us now explore the different ways to express the concentration of a solution, and understand where and why each method is more suitable.

Collect some commercial packaged products (Fig. 5.4) and note down the information given for each item.

The concentration of a solution can be expressed in several ways, a common one being the percentage which we are discussing here. You will learn about other methods in higher grades.

Next Level

Up

The three main ways to express the concentration of a solution in terms of percentage are given below.

A. Mass by mass percentage (% m/m or % w/w) This method is commonly used to express the concentration of homogeneous mixtures. It tells us how many grams of solute are present in 100 grams of the total solution.

This can be expressed mathematically as,

Mass of solutionMass of solute100= (5.1)

×Mass by mass percentage

(a)

This method of expressing concentration is also used for heterogeneous mixtures, such as milk powder (Fig. 5.4a) and spice mixtures. It is also used to label the composition of packaged foods, showing how much salt, sugar, or protein is present in them.

Example 5.1: If 10 g of salt is dissolved in 90 g of water, calculate the mass by mass percentage of the solution formed.Answer: Mass of salt (solute) = 10 g

Mass of water (solvent) = 90 gTotal mass of solution = Mass of solute + Mass of solvent= 10 g + 90 g = 100 g

×Mass by mass percentageMass of solutionMass of solute100=

×%/ggm m100

1010010==

(b)

B. Mass by volume percentage (% m/v or % w/v) This method is used where measuring the volume of a liquid is easier than weighing it, for example, in medicines and laboratories. A common example is 5% glucose solution (Fig. 5.4b). It tells us how many grams of the solute is present in 100 millilitres of the solution.

Mathematically,

Volume of solutionMass of solute100= (5.2)

×Mass by volume percentage

Example 5.2: If 5 g of glucose is dissolved in water to make 100 mL of solution, calculate its concentration in mass by volume percentage.Answer: Mass of glucose (solute) = 5 g

Volume of solution = 100 mL

Volume of solutionMass of solute100=

×Mass by volume percentage

(c)

Fig 5.4

×%/mLgm v10051005==

of some commercial

packaged products

(a) milk powder, (b) glucose solution, and

(c) vinegar

Threads of Curiosity

C. Volume by volume percentage (% v/v) This method is used when two miscible liquids are mixed, for example, in perfumes, cosmetics and vinegar (Fig. 5.4c). The volume by volume percentage (% v/v) tells us how many millilitres of the solute is present in 100 millilitres of the solution.Mathematically,

A saline drip in hospitals is usually 0.9 % m/v sodium chloride (common salt) in water. That means 0.9 g of salt in 100 mL of solution (Fig. 5.5). 0.9% saline solution is safe for blood and replaces lost fluids in the body.Fig. 5.5: Saline

Volume of solutionVolume of solute100= (5.3)

×Volume by volume percentage

Example 5.3: If 1 mL of a liquid pesticide is mixed with a sufficient amount of water to form 100 mL of a pesticide spray for rice crop, calculate its volume by volume percentage.Answer: Volume of pesticide (solute) = 1 mL

Total volume of solution = 100 mLVolume by volume percentage

×Volume of solutionVolume of solute100=

×% /mLmLv v10011001==

solution

Note

Commonly used unit in industries is weight by weight percentage (% w/w), as weight and mass are generally used interchangeably. Numerically, both % m/m and % w/w are equal to each other.

Pause and Ponder

1. A common talcum powder contains 4 % m/m zinc oxide, which acts as an antiseptic. How

much zinc oxide is present in 300 g of the talcum powder?2. Your mother gives you a bottle of orange juice concentrate to mix with water and serve it to

your visiting friends. She asks you to mix two tablespoons of the concentrate with water in a glass tumbler. If each tablespoon measures 15 mL and you make 150 mL of juice per person, what is the % v/v of orange juice concentrate in the mixture you prepared?3. Vinegar, used as a food preservative and additive, contains 5 % v/v acetic acid. Glacial acetic

acid is a liquid, i.e., 100% acetic acid. If you want to make vinegar from glacial acetic acid, how would you proceed?

5.2.3 Solubility of substances

You have learnt that the maximum amount of solute that dissolves in a fixed quantity of the solvent (100 mL or 100 g) is called its solubility at a given temperature. A solution that cannot dissolve any more solute at that temperature is called a saturated solution. Why do we mention the temperature? This is because the solubility of a solid solute in a liquid solvent generally increases with temperature. On the other hand, in the case of gases dissolved in liquids, their solubility generally decreases with an increase in temperature. Solubility is an important property used to separate substances from mixtures. Let us explore it further!

Grade 8CuriosityChapter 9

Activity 5.2: Let us represent solubility graphicallyConsider water as the solvent, and compounds ‘A’ and ‘B’ as the solutes. Each substance has a different solubility. A graph of solubility versus temperature is called a solubility curve. The solubility curves for ‘A’ and ‘B’ as solutes are shown in Fig. 5.6. The x-axis shows temperature (°C), whereas the y-axis indicates the solubility of the solute in grams per 100 g of water.

Compound ‘B’

Solubility (g per 100 g water)

Compound ‘A’

1020304050607080

Temperature (°C)

Fig. 5.6: Solubility curves of compounds ‘A’ and ‘B’ in water

Based on the information from the above graph, predict which of the two compounds, ‘A’ or ‘B’, will dissolve more in a given amount of water at a given temperature?

Observe Fig. 5.6 and fill in the blanks of the following statements:

(i) The solubility of compound ‘A’ in water at 20 °C is ______________ (less

than/more than/similar to) its solubility at 60 °C.(ii) The solubility of compound ‘B’ at 20 °C is ____________ (less than/

more than/similar to) its solubility at 60 °C. (iii) The solubility of _____________ increases more than that of ______________ with an increase in the temperature.What do you think will happen if you make a saturated solution at a higher temperature and cool it slowly? Let us find out!

5.3 Methods of Separation of Homogeneous Mixtures

5.3.1 Crystallization

You have learnt to prepare a saturated solution. If you take a saturated solution of compound ‘B’ in water at 60 °C, prepared by dissolving 287 g of compound ‘B’ in 100 g of water, what will happen if you gradually cool it to 40 °C? As per Fig. 5.6, the solubility of compound ‘B’ is 241 g per 100 g of water at 40 °C. It implies that only 241 g of compound ‘B’ can remain in the solution and the rest of it will separate out as a pure solid, often as crystals. A crystal is a solid that is made up of particles arranged in a regular geometric pattern.

Grade 8CuriosityChapter 9

You might have observed many types of crystals in everyday life, such as rock salt crystals (Fig. 5.7a) or sugar crystals (Fig. 5.7b) that grow while making candy sugar (called mishri in Hindi). Snowflakes are also crystals, formed when water vapour freezes in the air. Even frost on windows is formed when water vapour turns into ice crystals (Fig. 5.7c). This is how crystals form naturally.

(a)

In laboratories, the process of forming crystals from a saturated solution is called crystallization. This method can be used for the separation of two solids, in which one of the compounds is present in small quantity and both are soluble in the same solvent. This method can also be used for purification of solids. The principle of purification by crystallization is based on the differences in the solubility of a substance at different temperatures.

(b)

Try creating your own crystals.

Note

Activity 5.3: Let us prepare

Sulfuric acid is required for the crystallization of only some salts.

1. Collect a sample of copper sulfate (blue vitriol). If

(c)

copper sulfate is unavailable, you can use common salt as an alternative.Safety first: Copper sulfate is toxic. Perform the experiment under adult supervision and do not touch it with your bare hands.

Fig 5.7

(a) rock salt, (b) candy sugar, and

(c) frost

2. Take 1 g of copper sulfate and place

it in a 100 mL beaker. Add 25 mL of water to the beaker and add a drop of dilute sulfuric acid. Gently heat the mixture in a water bath while stirring constantly. Sulfuric acid helps in making pure crystals by preventing unwanted reactions. Safety first: It is advised that the teacher should add a drop of sulfuric acid. Handle sulfuric acid very carefully!

Glass rod

Beaker

Glass rod

Copper

Water

bathConical

sulfate solution

funnel

Tripod

Beaker

stand

Burner

Laboratory

3. Gradually, add more copper sulfate until the solution becomes saturated (Fig. 5.8a).4. Filter the hot solution to remove

stand

(a) Preparing the saturated

(b) Filtering the hot saturated

insoluble impurities (Fig. 5.8b). Collect it in a clean beaker and cover it with a watch glass.5. Allow the solution to cool slowly

solution

solution

Watch

glass

Watch

without disturbing it (Fig. 5.8c). It gives enough time to the particles in the solution to come together, resulting in the formation of larger, shiny, well-shaped and blue-coloured crystals. 6. Filter the crystals, rinse them with

glass

Beaker

Copper

sulfate crystals

Filtrate

(c) Cooling down the filtrate (d) Crystals of copper sulfate

cold water and allow them to dry on a watch glass (Fig. 5.8d).

Fig. 5.8: Steps involved in the process of crystallization

You may also try:

1. Place 1 – 2 mL of the saturated copper sulfate solution on a small glass

plate or a lamination sheet.2. Leave it for some time. What do you observe?

Did you get crystals? If yes, is this a good way to experiment? Explain. Crystallization is a common technique for separating pure substances (crystals) from homogeneous mixtures. When new compounds are prepared, they are often accompanied by unwanted impurities. Crystallization helps to separate the desired pure substance from the undesired impurities.

Think as a Scientist

If a hot, saturated solution of copper sulfate is cooled rapidly in ice-cold water, smaller and less well-formed crystals will form than if it is cooled slowly at room temperature. How would you design and perform an experiment to test this hypothesis?

Hint: Prepare a hot saturated solution of copper sulfate and divide it into two equal parts.

Pause and Ponder

4. Refer to the solubility curves given in Activity 5.2. If equal masses of hot, saturated solutions

of compounds ‘A’ and ‘B’ are cooled from 80 °C to 60 °C, which solution is likely to deposit more solid? 5. Will there be any change in the size of common salt crystals if the rate of evaporation is

increased or decreased? Explain.

Activity 5.4: Let us describe a processObserve Fig. 5.9, it shows how salt crystals are obtained from seawater. Can you describe the process in your own words?

SeawaterSaturated

solutionSalt crystals

Fig. 5.9: Steps followed in the salt manufacturing process

Ready to Go Beyond

Have you visited a place where large crystal deposits can be observed in nature? Such crystals can be found in various locations, including mines, caves and even within the Earth’s crust. One such example is the Mawsmai Cave (Fig. 5.10a) in Sohra (Cherrapunji), known for its fascinating natural formations. Quartz (Fig. 5.10b) is also one of the beautiful crystals found in nature.

(a)(b)

Fig. 5.10: Naturally occurring crystals (a) in caves and (b) quartz

India’s Scientific Contributions

When we allow a solvent to evaporate to get a solute, such as salt from a salt solution, the solvent disappears. However, we may also want to recover the solvent. What should we do then?

Crystallization of salt was an ancient process used by the local communities of the coastal areas in India. The panga salt was obtained by boiling concentrated sea brines, while the evaporation of sea water produced the karkatch salt. Salt crystals of different sizes were produced by these methods.

While experimenting in the laboratory, a student accidentally mixed acetone and water, two miscible liquids. How can we separate the two miscible liquids? Is it possible to separate the mixture of two miscible liquids by evaporation and obtain both the liquids?

5.3.2 Distillation

A homogeneous mixture of two miscible liquids can be separated by heating the mixture until the liquid with the lower boiling point vaporises. The vapour is then cooled, turning back into liquid (Fig. 5.11). This process is known as distillation. It allows the recovery of the solvent or the separation of liquids that differ in boiling point by at least about 25 °C. This method can also be used to separate a liquid from a solution containing dissolved solids.

Liquid

Heating

During the process, vapours of the lower-boiling liquid are passed through a condenser where they are cooled, usually by circulating water or air and condensed as a pure liquid. The pure liquid is collected in a separate vessel, while the solid or other liquid from the mixture remains in the distillation flask. A distillation set-up is shown in Fig. 5.12.

Vapour

Cooling

Liquid(Distillate)

Fig 5.11

Thermometer

Water outlet

Laboratory

stand

Water condenser

Distillation flask

Water inlet

Mixture of acetone and water

Wire gauze

Tripod stand

Conical flask

Burner

Acetone

A mixture of acetone and water can be separated by distillation because their boiling points differ sufficiently. Acetone boils at about 56 °C and water boils at 100 °C. A large difference in boiling points allows one liquid to vaporise before the vapours of the other liquid are formed in significant amount.

India’s Scientific Contributions

The process of distillation has been used for a long time for various purposes, including extraction of fragrances from flowers to make perfumes.

You must have noticed the pleasant earthy smell that rises from the ground after the first rain. In Kannauj, a town in Uttar Pradesh known as the perfume capital of India, this beautiful fragrance is captured and turned into a natural perfume called Mitti ka Ittar (earthy fragrance). This perfume is made using a traditional distillation method known as the Deg-Bhapka method (Fig. 5.13), which has been passed down through generations in Kannauj. It is in great demand, both in India and around the world. The Fragrance and Flavour Development Centre in Kannauj has facilities for separating flavour and fragrance components from flowers, leaves and other parts of plants. It also supports farmers in cultivating fragrance-producing plants and offers expertise to those looking to establish their own perfume businesses.

Fig 5.13

Ready to Go Beyond

A petroleum refinery (Fig. 5.14a) is an industrial unit where crude oil is processed to obtain various useful petroleum products. Petroleum products are mixtures of useful gases and liquids, such as petroleum gas, petrol, kerosene, diesel, etc. Crude petroleum is extracted from the Earth’s crust and separated into these different fractions using the process of fractional distillation (Fig. 5.14b). Fractional distillation is the process of separating components of a mixture with relatively small differences (less than 25 °C) in their boiling points. The gaseous fraction is filled in steel cylinders under high pressure, where it gets liquefied. It is used as domestic fuel in the form of Liquefied Petroleum Gas (LPG).

Petroleum gas

Petrol

Aviation fuel

(Kerosene)

Diesel

Crude

oil

Lubricating oil

Furnace

Bitumen

(a)

(b)

Fig. 5.14: (a) Petroleum refinery, and (b) products of fractional distillation of crude petroleum

Threads of Curiosity

5.3.3 Paper Chromatography

Have you ever observed what happens when a drop of water falls on something written with a sketch pen on a paper? You may have noticed that the colour spreads. If the sketch pen is black, different colours might spread out. If you have not noticed this before, try it now!Activity 5.5: Let us investigate

The word ‘chromatography’ comes from the Greek words chroma, meaning ‘colour’ and graphein, meaning ‘to write’. It actually means ‘writing with colour’ because it was first used to separate coloured substances like dyes and inks.

1. Take a 3 cm wide strip of chromatographic paper and draw

a straight, horizontal line, 2 cm from the bottom of the paper with a pencil (Fig. 5.15a). Alternatively, you can use a strip of filter paper.2. Mark a spot with a black sketch pen at the centre of the line

(Fig. 5.15b).

3. Take enough water to make a thin

layer at the bottom of a gas jar, a measuring cylinder, or a beaker.4. Place the paper strip with the ink

Watch

glass

Chromatographic

spot vertically into the container, so that its lower end dips into the water. The water level should be below the spot, as shown in Fig. 5.15c.5. Observe the paper as the water rises

paper

Gas jar

Water

Ink spot

Line drawn

through the paper. What do you notice?6. As the water rises, the ink starts to

with pencil

(a)(c)

(b)

Fig 5.15

separate into different colour spots. What can you infer from this? This method of separating the components of a mixture is known as paper chromatography. It uses differences in the interactions of the components with the solvent and the paper to separate them. The liquid carries the substances up the paper, separating them based on how fast they move. You can also try this with green food colour instead of black ink and use a 2 % m/v salt solution as the solvent.

Similarly, you can separate different pigments present in the green extract of spinach leaves or coloured pigments from the flower petals. Will water work as a solvent in every case? In some cases, you may need to use a different solvent, such as alcohol or a mixture of solvents.

Pause and Ponder

6. State whether the following statements are True or False. Also, correct the False statements.

(i) Salt can be separated from a salt solution by evaporation or distillation.(ii) Distillation can be used for separation of two liquids even when these have the same

boiling point.(iii) In paper chromatography, the solvent level should be above the sample spot at the

beginning of the experiment.(iv) Evaporation and crystallization are the same processes.

5.4 How Can We Separate the Components of Heterogeneous Mixtures?

5.4.1 Separation of two immiscible liquids

You have learnt about non-uniform mixtures. Have you noticed what happens when water falls into a container that has oil? The oil and water form separate layers. They do not mix and are called immiscible liquids. Similarly, sand and water do not mix, nor do iron filings and sulfur. These are examples of heterogeneous mixtures.

Grade 8CuriosityChapter 9

How can you separate the components of a mixture of two immiscible liquids?

Let us try to separate mustard oil from water.

Activity 5.6: Let us separate

Laboratory stand

1. Pour a mixture of 5 mL mustard oil and

20 mL water into a 50 mL separating funnel. 2. Let it stand undisturbed. What do you

Separating funnel

observe?3. You will see the formation of two separate

Mustard oil

layers of mustard oil and water (Fig. 5.16). The yellow-coloured mustard oil forms the upper layer and water forms the lower layer. Can you explain why?4. Open the stopcock of the separating funnel

Water

Stopcock

Conical flask

slowly to collect the lower layer of water carefully into a container.5. Close the stopcock when the water is almost

Glass stopper

fully drained.6. Collect the next small portion that may

Fig 5.16

contain both liquids and discard it.7. Collect the layer of oil separately by opening the stopcock again.You now have two separate liquids.

Can you think of any heterogeneous mixtures with a gas as one of the components?

Gas particles are free to move in all directions, so they mix easily and uniformly with other gases. Hence, most mixtures of gases are homogeneous, such as a mixture of hydrogen and oxygen, which is used as a rocket fuel. On the other hand, smoke (solid particles suspended in air), fog (tiny liquid water droplets present in air) and dust in the air are some heterogeneous mixtures with gas as one of the components.

What if …

two immiscible liquids of the same density are mixed in a separating funnel, how will the layers form?

Most of the solid-solid mixtures are heterogeneous. You can use a property of one of the solids to separate the mixture. You have learnt how to separate iron nails from sawdust using a magnet. Now, let us explore another technique to separate solid-solid mixtures.

Grade 6CuriosityChapter 9

5.4.2 Sublimation

Activity 5.7: Let us explore

1. Take a spatula full of the mixture containing crushed camphor and

sand. Put it into a clean and dry china dish. Place it on the tripod stand using a wire gauze.

2. Take a clean and dry glass funnel. Plug its

Cotton plug

nozzle with cotton.3. Keep this funnel inverted on the china dish

Glass funnel

and set up the apparatus as shown in Fig. 5.17. 4. Light the burner and place it under the wire

gauze.5. Heat the china dish gently for a few minutes.6. Observe the inner wall of the funnel carefully.

China dish containing mixture of camphor and

sand

Wire gauze

Do you notice any solid deposits?7. You may find white, solid camphor deposits

Tripod stand

on the inner wall of the funnel while sand remains in the china dish. Camphor, on heating (below its melting point), changes directly from the solid state to the vapour state without passing through the liquid state, this process is called sublimation. On cooling, vapours condense back into a solid without becoming a liquid, this is called deposition. Hence, camphor sublimes and separates from sand because sand does not sublime on heating.

Burner

Fig 5.17

You can also perform this activity using any other sublimable substance, such as naphthalene, in place of camphor.

Similarly, solid carbon dioxide, known as dry ice which is used for ice cream storage, also undergoes sublimation. Can you think of any other mixtures where sublimation can be used to separate the components?

Is it possible to dissolve one metal in another?Metals do not dissolve into each other at room temperature. However, when metals are melted at high temperatures, they can be mixed to form a solution. When such a hot mixture of two or more metals cools, it solidifies into a new material that appears to be a single metal. A homogeneous mixture of two or more metals, or a metal and a non-metal, is called an alloy. Physical methods cannot separate the components of an alloy. Alloys

are generally prepared to produce materials that are stronger, more rigid, or more corrosion-resistant. Common examples of alloys include brass — a mixture of approximately 80% copper and 20% zinc; bronze — a mixture of approximately 80% copper and 20% tin; stainless steel — usually a mixture of iron and other elements, such as carbon (about 0.03 – 0.8%), chromium (16 – 18%), nickel (10.0 –14.0%) and molybdenum (2.0 – 3.0%).

Pause and Ponder

7. Why do immiscible liquids

form two separate layers in a separating funnel?8. Is sublimation different

from evaporation? Justify.

5.4.3 Suspensions

Let us look closely at the container shown in Fig. 5.2. No matter how well you stir, the sand particles can be seen clearly, unlike in a solution, where the solute particles are not visible. Such heterogeneous mixtures in which the solid particles (sand) do not dissolve but remain suspended throughout the bulk of the medium (water) are called suspensions. In the case of a suspension, the particles of the undissolved substance are larger in size than the particles present in the solution. Particles of a suspension are visible to the naked eye. Some other examples of suspension are sawdust suspended in water and tea leaves in water.

How can we separate mud from water?If you leave a container of muddy water undisturbed, the heavier mud particles settle at the bottom and the water may still appear cloudy. You can filter the muddy water through a cotton cloth or filter paper. While some larger particles will be removed, the water often remains cloudy. This shows that filtration is not always enough to separate tiny particles. If the muddy water is still not clear even after keeping for some time, how can it be cleaned? In such cases, we use techniques, such as centrifugation and/or coagulation.

Let us explore these processes!

Threads of Curiosity

A. CentrifugationLet us understand this by playing a game. Choose a partner. Then, cross your arms and hold each other’s hands as shown in Fig. 5.18. Now spin around together. Do you feel as if you are being pulled outwards? A similar force helps to separate a mixture in a tube by centrifugation. This process involves spinning a mixture in a tube at a high speed (Fig. 5.19). During centrifugation, the tubes become horizontal and the centrifugal force (outward force acting on a body moving in circular motion) causes the heavier particles to move outwards, where they settle at the bottom of the tube, while the lighter liquid remains at the top.

The spinning game is a folk dance called phugadi in Marathi and kikli in Punjabi. What is this called in your local language?

Fig 5.18

(b)

(a)

Fig. 5.19: Centrifugation machine (a) outer view and (b) inner view

Centrifugation is widely used in laboratories to separate the components of blood, such as red blood cells and plasma, and in many chemical industries.

Bridging Science and Society

The PaperfugeCentrifugation is usually done using an electric machine but by applying ideas from a common toy, a simple hand-powered device called a paperfuge (Fig. 5.20) can perform the same process without electricity. By spinning the blood samples at a very high speed, the paperfuge separates heavier components from lighter ones, just like a laboratory centrifuge. This low-cost tool can help detect diseases like malaria and anaemia in remote areas. Find out more about such simple technological inventions that improve access to medical care in remote places.

Blood sample

Tape

String

HandleCardboard disc

Fig 5.20

Activity 5.8: Let us make a modelMake your own centrifuge with a cardboard disc and thick thread. You will be able to see how the heavier particles move outwards. It is a fun and hands-on way to understand the science behind separation. Which mixture would you like to separate using this mini centrifuge?

Powdered

alum

Muddy

B. CoagulationPowdered alum (fitkari) can be added to a beaker containing muddy water (Fig. 5.21a). Alum is a white crystalline chemical substance often used in water purification. The alum causes the fine suspended particles to clump together. This process is called coagulation and the alum is said to act as a coagulant (Fig. 5.21b). These larger clumps thus formed, settle by gravity (sedimentation), as shown in Fig. 5.21c and can be separated from water by decantation or filtration.

water

(a) Adding powdered

(b) Alum coagulates

alum to suspended impurities in water

the suspended

impurities

Settled impurities

(c) Impurities settle at the bottom

Fig 5.21

Can you think of any other coagulation processes used in everyday life?The formation of cheese (paneer) from milk also involves coagulation, in which acid (lemon juice or vinegar) is used as a coagulant. It causes the coagulation of milk proteins, forming cheese.

5.4.4 Colloids

If the components of blood can be separated by centrifugation and the blood coagulates, is it a suspension? However, we cannot see blood cells with the naked eye. Is it a solution?

Blood is neither a solution nor a true suspension. It is a colloid. Some other examples of colloids are milk, tomato sauce and ice cream.

Bridging Science and Society

Donate Blood

Donating blood saves lives. People in emergencies, during surgeries, or with serious illnesses may need a blood transfusion, which is the transfer of blood from a healthy person to a patient.

Blood sample

Test tube stand

Donated blood is tested and when the blood group is identified, it is separated into its components, such as plasma, platelets, white and red blood cells (Fig. 5.22). These are stored safely in blood banks and supplied when required. In Chapter 3, Tissues in Action, you have learnt that blood connects different parts of the body by transporting nutrients, gases and hormones.

(a)

PlasmaPlatelets and white blood cells

Red blood cells

The body replaces the donated blood naturally within a few weeks, making blood donation safe and helpful.

(b)

Fig. 5.22: Components of blood (a) before centrifugation and (b) after centrifugation

Do you know your blood group? Find out!

Let us try to understand what colloids are. How are they different from solutions and suspensions? Can you think of some other substances that could be colloids?

Solutions, suspensions and colloids (Fig. 5.23) differ mainly in the size of the dissolved or the suspended particles. The particle size of a solute is the smallest (less than 1 nm diameter) in a solution. Colloids have larger particles (1 – 1000 nm), while suspensions have much larger particles (more than 1000 nm in diameter).

(a)(b)(c)

Fig. 5.23: (a) Solution, (b) suspension, and (c) colloid

Unlike suspension, the particles in a colloid do not settle over time from the mixture. They are uniformly dispersed throughout the mixture as in a solution.

5.5 Tyndall Effect

Let us go back to Activity 5.1. What happened to the thin beam of laser light when it was passed through the beakers containing the mixtures? You might have observed that the path of the light beam was not visible in solution A. The particles in suspension B scattered (spread) the beam of light making its path visible. In mixture C too, the path of light was visible, indicating that the particles scattered the light, though the mixture appeared homogeneous.

Have you ever observed light scattering by particles in your surroundings? The scattering of light by particles is known as the Tyndall effect. It is called so because it was first explained by the scientist John Tyndall, who studied the scattering of light by particles.

This effect can also be observed when a fine beam of light enters a dark room through a small hole. This happens because light gets scattered by

the dust and smoke particles in the air. You might have also observed this phenomenon in the floodlights in a sports stadium (Fig. 5.24). Think of some more examples!

Scattering of light occurs when it passes through a colloid or a suspension but not when it passes through a transparent solution.

The components of a colloid are called the dispersed phase and the dispersion medium. The solute-like component or the dispersed particles, in a colloid form the dispersed phase and the component in which the dispersed phase is suspended is known as the dispersion medium.

Fig. 5.24: Demonstration of Tyndall effect in

a sports stadium

Threads of Curiosity

Some common colloids we encounter in our daily lives have both the dispersed phase and the dispersion medium as liquids. These are called emulsions. Emulsions containing oil and water are further classified as oil-in-water or water-in-oil, depending on the nature of the dispersed phase and the dispersion medium. Milk and vanishing creams are common examples of oil-in-water emulsions, whereas butter, body lotions, cold cream, etc., are examples of water-in-oil emulsions. Some medicines are prepared as emulsions to disperse them in water and make them easily palatable. This also reduces the greasy feeling of the liquid medicine.

The presence of emulsifying agents stabilises emulsions. For example, proteins in milk and butter act as emulsifying agents.

You can make an emulsion by thoroughly mixing and shaking a few drops of cooking oil with water containing a few drops of soap solution.

Pause and Ponder

9. Clouds are made up of tiny water droplets or ice crystals floating in the air. Based on what you

know about solutions, suspensions and colloids, what type of mixture do you think clouds are and why? 10. Why do cities with a lot of smoke and dust in the air often look hazy?

Activity 5.9: Complete Table 5.1 and review what you have learnt about solutions, suspensions and colloids.

Table 5.1

S. No.PropertySolutionSuspensionColloid

1.Nature (homogeneous/heterogeneous)

2.Particle size

3.Visibility

4.Separation by filtration

5.Settling

6.Tyndall effect

We use various properties, such as size, density and solubility to separate mixtures. However, separation is not always simple. Imagine trying to separate all the ingredients in a lemonade once they have been mixed. Can you do it?

Do you know that separation happens in nature and in our bodies, too? For example, our kidneys remove waste from our blood. Today, we face bigger challenges like cleaning oceans and rivers by removing plastic waste. It is also essential to treat sewage water before releasing it into the environment. Sewage treatment involves steps, such as sedimentation, coagulation and filtration. Clean water obtained in this way can be reused for flushing toilets or watering plants.

Another important task is sorting or segregating the waste at home. Dry waste, such as plastic, paper, glass and metal can be recycled, while wet waste like food scraps, vegetable peels, etc., can be composted. Researchers are also finding ways to recover valuable materials, such as lithium from old batteries used in mobile phones and laptops.

By improving the methods for separating waste and recycling materials, you can help make the world cleaner, healthier and more sustainable.

At a Glance

y

Mixtures are classified as homogeneous or heterogeneous and also

as solutions, suspensions, or colloids. • Separation of mixtures is a crucial process for obtaining pure

substances. • Crystallization is a technique used to get a pure solid from its

saturated solution. • Distillation is used to separate two miscible liquids with a

minimum difference of 25 °C in boiling points. It can also be used to obtain a liquid from a mixture of a liquid and a solid. • Paper chromatography can be used to separate compounds by

taking advantage of differences in their rates of movement on the paper. • A separating funnel is used to separate two immiscible liquids

based on their different densities. • The transition of a solid directly into a vapour (below its melting

point) without passing through the liquid state is called sublimation. The process when the vapour cools and changes back into a solid without becoming a liquid is called deposition. • Centrifugation uses rapid spinning to separate heavier solid

particles from a solid-liquid mixture. • Coagulation involves the addition of a substance, called a coagulant,

to make smaller particles clump together and settle down in a heterogeneous mixture of solids and liquids. • The dispersed particles in a colloid or suspension scatter light,

which is known as the Tyndall effect.