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NCERT Solutions for Class 5th Maths Chapter 1 Questions 1 to 9 — Let Us Do

Book page 13–15 Updated on2026-09-19

Q1.
1. Write 5 numbers between the numbers 23,568 and 24,234.
Answer

Sample answer: 23,600 · 23,750 · 23,900 · 24,000 · 24,150

How to choose them — 3 steps.

  1. The numbers must be bigger than 23,568 and smaller than 24,234.
  2. Start just above 23,568 and walk upwards, keeping well inside the two ends.
  3. Check each one: 23,568 < 23,600 < 24,234 ✓ … and so on for all five.
23,568 < 23,600 < 23,750 < 23,900 < 24,000 < 24,150 < 24,234
Tip: There is no single right answer. Any five numbers from 23,569 up to 24,233 will do. That is 665 numbers to choose from.
Q2.
2. Write 5 numbers that are more than 38,125 but less than 38,600.
Answer

Sample answer: 38,200 · 38,300 · 38,400 · 38,500 · 38,550

How to choose them.

  1. All five numbers start with 38, because both ends do.
  2. The last three digits must be more than 125 and less than 600.
  3. Pick easy ones: 200, 300, 400, 500, 550.
38,125 < 38,200 < 38,300 < 38,400 < 38,500 < 38,550 < 38,600
Careful: 38,600 itself is not allowed. The question says less than 38,600, not up to it.
Q3.
3. Ravi's car has been driven for 56,987 km till now. Sheetal's car has been driven 67,543 km. Whose car has been driven more?
Answer

Sheetal's car has been driven more.

Step 1 — count the digits. Both numbers have 5 digits, so we must compare place by place.

Step 2 — start from the left.

TThThHTO
Ravi 56,98756987
Sheetal 67,54367543
In the TTh column: 6 is more than 5
So 67,543 > 56,987 → Sheetal's car

Step 3 — how much more?

67,543 – 56,987 = 10,556 km more
Careful: Do not be tricked by the 9 and 8 in Ravi's number. Those sit in the hundreds and tens places. The ten-thousands place decides first, and it decides for Sheetal.
Q4.
4. The following are the prices of different electric bikes. Arrange the prices in ascending (increasing) order. ₹90,000 · ₹89,999 · ₹94,983 · ₹49,900 · ₹93,743 · ₹39,999
Answer

Ascending order means cheapest first.

₹39,999 < ₹49,900 < ₹89,999 < ₹90,000 < ₹93,743 < ₹94,983

How to sort them — 3 steps.

  1. Group by the ten-thousands digit: 3 → 39,999 · 4 → 49,900 · 8 → 89,999 · 9 → 90,000; 94,983; 93,743.
  2. Order the groups: 3, then 4, then 8, then all the 9s.
  3. Sort inside the group of 9s by the next digit: 90,000 (0), 93,743 (3), 94,983 (4).
The tricky pair: ₹89,999 and ₹90,000 look almost the same in size and differ by only ₹1. But 8 is less than 9 in the ten-thousands place, so ₹89,999 comes first. A single rupee decides the order.
Check it yourself: The cheapest bike costs ₹39,999 and the costliest ₹94,983. The difference is 94,983 – 39,999 = ₹54,984.
Q5.
5. The following table shows the population of some towns. Arrange them in a descending (decreasing) order.
TownPopulation
Town 165,232
Town 253,231
Town 356,380
Town 451,336
Town 545,858
Town 666,540
The population table printed on page 14.
Answer

Descending order means biggest first.

66,540 > 65,232 > 56,380 > 53,231 > 51,336 > 45,858
PlaceTownPopulation
1st (largest)Town 666,540
2ndTown 165,232
3rdTown 356,380
4thTown 253,231
5thTown 451,336
6th (smallest)Town 545,858

How to sort them.

  1. Ten-thousands digits are 6, 5, 5, 5, 4, 6. The 6s are biggest, then the 5s, then the 4.
  2. Between the two 6s — 66,540 and 65,232 — look at the thousands: 6 beats 5. So 66,540 first.
  3. Among the three 5s — 56,380 · 53,231 · 51,336 — the thousands are 6, 3 and 1. So the order is 56,380, then 53,231, then 51,336.
Check it yourself: Read your answer backwards. It should be the ascending order: 45,858 · 51,336 · 53,231 · 56,380 · 65,232 · 66,540 ✓
Q6.
6. Find numbers between 42,750 and 53,500 such that the ones, tens, and hundreds digits are all 0.
Answer

There are 11 such numbers:

43,000 · 44,000 · 45,000 · 46,000 · 47,000 · 48,000 · 49,000 · 50,000 · 51,000 · 52,000 · 53,000

How to find them — 3 steps.

  1. If the ones, tens and hundreds digits are all 0, the number ends in 000. So it is a whole number of thousands.
  2. The smallest whole thousand above 42,750 is 43,000.
  3. The largest whole thousand below 53,500 is 53,000. Now list every thousand in between.

Count them:

From 43,000 to 53,000, counting in thousands:
53 – 43 = 10, and adding 1 for the starting number gives 11 numbers ✓
Careful: 42,750 is not a whole thousand, so it is not on the list. Neither is 53,500. And 54,000 is beyond the upper end, so it does not count either.
Q7.
7. Write the following numbers in the expanded form. One has been done for you: (a) 783 = 700 + 80 + 3. (b) 8,062 =
Answer

8,062 = 8,000 + 60 + 2

Step 1 — put each digit in its place.

ThHTO
8062

Step 2 — write what each digit is worth.

8 in the thousands place = 8,000
0 in the hundreds place = 0
6 in the tens place = 60
2 in the ones place = 2

Step 3 — add them, leaving out the zero.

8,062 = 8,000 + 60 + 2
Tip: You may also write 8,000 + 0 + 60 + 2. Both are correct, but a 0 adds nothing, so it is usually left out.
Q8.
7. (c) 9,980 =
Answer

9,980 = 9,000 + 900 + 80

9 thousands = 9,000
9 hundreds = 900
8 tens = 80
0 ones = 0
9,000 + 900 + 80 = 9,980 ✓
Check it yourself: Add the parts back up. 9,000 + 900 = 9,900, and 9,900 + 80 = 9,980 ✓
Q9.
7. (d) 10,304 =
Answer

10,304 = 10,000 + 300 + 4

TThThHTO
10304
1 ten thousand = 10,000
0 thousands = 0
3 hundreds = 300
0 tens = 0
4 ones = 4
10,000 + 300 + 4 = 10,304 ✓
Why we still write the zeros in the number: The zeros do not add anything, but they hold the 1 and the 3 in their proper places. Take them out and you get 134, a completely different number.
Q10.
7. (e) 23,004 =
Answer

23,004 = 20,000 + 3,000 + 4

2 ten thousands = 20,000
3 thousands = 3,000
0 hundreds = 0
0 tens = 0
4 ones = 4
20,000 + 3,000 + 4 = 23,004 ✓
Tip: Read the number name out loud — twenty-three thousand four. The name tells you the same story: twenty thousand, three thousand, and four.
Q11.
7. (f) 70,405 =
Answer

70,405 = 70,000 + 400 + 5

TThThHTO
70405
7 ten thousands = 70,000
4 hundreds = 400
5 ones = 5
70,000 + 400 + 5 = 70,405 ✓
Check it yourself: 70,000 + 400 = 70,400, and 70,400 + 5 = 70,405 ✓
Q12.
8. Fill in the blanks with the correct answer. Share your thoughts in class. (a) 983 = 90 Tens + 83 Ones. (b) 68 = ___ Tens + 18 Ones
Answer

68 = 5 Tens + 18 Ones

Step 1 — work out what the given part is worth.

18 Ones = 18

Step 2 — take it away from the number.

68 – 18 = 50

Step 3 — turn what is left into tens.

50 = 5 Tens → the blank is 5

Check: 5 Tens + 18 Ones = 50 + 18 = 68 ✓

What is going on here: Usually we write 68 as 6 tens and 8 ones. But we are allowed to break it up differently — 5 tens and 18 ones is the same amount. One ten has simply been unbundled into 10 ones. This is exactly the idea behind borrowing in subtraction.
Q13.
8. (c) 607 = 4 Hundreds + ___ Ones
Answer

607 = 4 Hundreds + 207 Ones

Step 1 — find what 4 Hundreds is worth.

4 Hundreds = 400

Step 2 — take it away.

607 – 400 = 207

Step 3 — the rest is counted in ones.

207 = 207 Ones → the blank is 207

Check: 400 + 207 = 607 ✓

Note on the Hindi book: In the Hindi edition this part is printed as 607 = सैकड़ा + ____ इकाई, with the number 4 missing before सैकड़ा. Read it as 4 सैकड़ा, exactly as in the English book.
Q14.
8. (d) 5,621 = 4 Thousand + ___ Hundreds + 2 Tens + ___ Ones
Answer

5,621 = 4 Thousand + 16 Hundreds + 2 Tens + 1 One

Step 1 — take away the parts you already know.

4 Thousand = 4,000
2 Tens = 20
5,621 – 4,000 – 20 = 1,601

Step 2 — split 1,601 into hundreds and ones.

1,601 = 1,600 + 1
1,600 = 16 Hundreds
1 = 1 One

Check: 4,000 + 1,600 + 20 + 1 = 5,621 ✓

Why 16 hundreds and not 6: The usual way is 5 thousands + 6 hundreds. But here only 4 thousands are allowed. The fifth thousand has to be unbundled into 10 hundreds, and 10 + 6 = 16 hundreds.
Q15.
8. (e) 7,069 = ___ Thousand + 20 Hundreds + ___ Ones
Answer

7,069 = 5 Thousand + 20 Hundreds + 69 Ones

Step 1 — find what 20 Hundreds is worth.

20 Hundreds = 20 × 100 = 2,000

Step 2 — take it away.

7,069 – 2,000 = 5,069

Step 3 — split what is left.

5,069 = 5,000 + 69
5,000 = 5 Thousand
69 = 69 Ones

Check: 5,000 + 2,000 + 69 = 7,069 ✓

Tip: 20 Hundreds is a big chunk — two whole thousands. Always turn the given part into a plain number first. Then the rest is easy.
Q16.
8. (f) 37,608 = ___ Ten Thousand + 17 Thousand + ___ Hundreds + 8 Ones
Answer

37,608 = 2 Ten Thousand + 17 Thousand + 6 Hundreds + 8 Ones

Step 1 — find what the given parts are worth.

17 Thousand = 17,000
8 Ones = 8

Step 2 — take them away.

37,608 – 17,000 – 8 = 20,600

Step 3 — split 20,600 into ten thousands and hundreds.

20,600 = 20,000 + 600
20,000 = 2 Ten Thousand
600 = 6 Hundreds

Check: 20,000 + 17,000 + 600 + 8 = 37,608 ✓

Why 17 thousands can appear: Normally 37,608 is 3 ten thousands + 7 thousands. Here one whole ten thousand has been broken into 10 thousands, so 7 + 10 = 17 thousands, and only 2 ten thousands are left.
Q17.
8. (g) 43,001 = 3 Ten Thousand + ____ Thousand + ____ Hundreds + 1 Ones
Answer

43,001 = 3 Ten Thousand + 13 Thousand + 0 Hundreds + 1 One

Step 1 — find what the given parts are worth.

3 Ten Thousand = 30,000
1 One = 1

Step 2 — take them away.

43,001 – 30,000 – 1 = 13,000

Step 3 — split 13,000 into thousands and hundreds.

13,000 = 13 Thousand and no hundreds
Thousands blank = 13, Hundreds blank = 0

Check: 30,000 + 13,000 + 0 + 1 = 43,001 ✓

Another correct answer: 12 Thousand + 10 Hundreds also makes 13,000, so 3 Ten Thousand + 12 Thousand + 10 Hundreds + 1 One is also right. Share both in class and see which one your friends found.
Q18.
9. Fill in the blanks with the correct answers. (a) How many notes of ₹10 are there in ₹7,934? — 793. (b) How many notes of ₹100 are there in ₹7,934?
Answer

79 notes of ₹100.

Step 1 — think in hundreds. One ₹100 note is worth 100 rupees, so ask how many hundreds fit inside 7,934.

7,934 ÷ 100
7,900 ÷ 100 = 79, and ₹34 is left over
So there are 79 notes of ₹100, with ₹34 left over.

Step 2 — the quick way. Cover the last two digits of 7,934 with your finger. What you can still see is 79.

Why covering works: The last two digits are the tens and the ones. They are worth less than 100, so they cannot make even one more hundred-rupee note. Everything to their left is counted in hundreds.
Check it yourself: 79 × 100 = 7,900, and 7,900 + 34 = 7,934 ✓
Q19.
9. (c) How many thousands are there in 7,934?
Answer

7 thousands.

7,934 ÷ 1,000
7,000 ÷ 1,000 = 7, and 934 is left over
So there are 7 thousands, with 934 left over.

The quick way: Cover the last three digits of 7,934. What remains is 7.

Check it yourself: 7 × 1,000 = 7,000, and 7,000 + 934 = 7,934 ✓
Tip: Notice the pattern so far — 793 tens, 79 hundreds, 7 thousands. Each time you cover one more digit from the right.
Q20.
9. (d) How many ₹500 notes are there in ₹7,934? (Hint: Observe the answer of (iii))
Answer

15 notes of ₹500 (with ₹434 left over).

Step 1 — use the hint. Part (c) told us that ₹7,934 holds 7 thousands.

Step 2 — turn each thousand into ₹500 notes.

₹1,000 = two ₹500 notes
7 thousands → 7 × 2 = 14 notes of ₹500 (that is ₹7,000)

Step 3 — deal with what is left.

7,934 – 7,000 = 934
934 is more than 500, so one more ₹500 note fits
14 + 1 = 15 notes

Step 4 — check.

15 × 500 = 7,500
7,934 – 7,500 = 434 left over, and 434 is less than 500, so no more notes fit ✓
Answer in one line: ₹7,934 can be given as 15 notes of ₹500 plus ₹434 in smaller money.
Q21.
9. (e) How many notes of ₹10 are there in ₹65,342?
Answer

6,534 notes of ₹10 (with ₹2 left over).

65,342 ÷ 10
65,340 ÷ 10 = 6,534, and ₹2 is left over

The quick way: Cover the last digit of 65,342. What remains is 6,534.

Why: The ones digit, 2, is less than 10, so it cannot make another ten-rupee note. Every digit to its left is already counted in tens.
Check it yourself: 6,534 × 10 = 65,340, and 65,340 + 2 = 65,342 ✓
Q22.
9. (f) How many notes of ₹100 are there in ₹65,342?
Answer

653 notes of ₹100 (with ₹42 left over).

65,342 ÷ 100
65,300 ÷ 100 = 653, and ₹42 is left over

The quick way: Cover the last two digits of 65,342. What remains is 653.

Check it yourself: 653 × 100 = 65,300, and 65,300 + 42 = 65,342 ✓
Q23.
9. (g) How many thousands are there in 65,342?
Answer

65 thousands (with 342 left over).

65,342 ÷ 1,000
65,000 ÷ 1,000 = 65, and 342 is left over

The quick way: Cover the last three digits of 65,342. What remains is 65.

Check it yourself: 65 × 1,000 = 65,000, and 65,000 + 342 = 65,342 ✓
Tip: The three answers line up neatly — 6,534 tens · 653 hundreds · 65 thousands. Each answer is the one before it with the last digit covered.
Q24.
9. (h) How many ₹500 notes are there in ₹65,342?
Answer

130 notes of ₹500 (with ₹342 left over).

Step 1 — use part (g). ₹65,342 holds 65 thousands.

Step 2 — each thousand is two ₹500 notes.

65 × 2 = 130 notes of ₹500 (that is ₹65,000)

Step 3 — deal with what is left.

65,342 – 65,000 = 342
342 is less than 500, so no extra note fits

Step 4 — check.

130 × 500 = 65,000
65,000 + 342 = 65,342 ✓
Compare with part (d): There the leftover was 934, which was more than 500, so one extra note was needed. Here the leftover is only 342, so no extra note is needed. Always look at the leftover before deciding.
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