EN हिं

NCERT Solutions for Class 5th Maths Chapter 4 Subtracting Large Numbers — Let Us Solve

Book page 50–51 Updated on2026-09-19

Q1.
Subtract the following. Try not to write TTh, Th, H, T, and O at the top. Align the digits carefully. (a) 4,578 – 2,222 (b) 15,324 – 11,780 (c) 5,423 – 423 (d) 123 – 12 (e) 77,777 – 777 (f) 826 – 752
Answer
SubtractionAnswerCheck by adding back
(a) 4,578 − 2,2222,3562,356 + 2,222 = 4,578 ✓
(b) 15,324 − 11,7803,5443,544 + 11,780 = 15,324 ✓
(c) 5,423 − 4235,0005,000 + 423 = 5,423 ✓
(d) 123 − 12111111 + 12 = 123 ✓
(e) 77,777 − 77777,00077,000 + 777 = 77,777 ✓
(f) 826 − 7527474 + 752 = 826 ✓

(a) 4,578 − 2,222 = 2,356

  1. Ones: 8 − 2 = 6. Tens: 7 − 2 = 5. Hundreds: 5 − 2 = 3. Thousands: 4 − 2 = 2.
  2. No regrouping was needed anywhere.

(b) 15,324 − 11,780 = 3,544

  1. Ones: 4 − 0 = 4.
  2. Tens: 2 is smaller than 8. Take 1 hundred from the 3 hundreds. Tens become 12, hundreds become 2. 12 − 8 = 4.
  3. Hundreds: 2 is smaller than 7. Take 1 thousand from the 5 thousands. Hundreds become 12, thousands become 4. 12 − 7 = 5.
  4. Thousands: 4 − 1 = 3.
  5. Ten-thousands: 1 − 1 = 0.

(c) 5,423 − 423 = 5,000

  1. Ones: 3 − 3 = 0. Tens: 2 − 2 = 0. Hundreds: 4 − 4 = 0. Thousands: 5 stays.
  2. Everything below the thousands cancels out, leaving 5,000.

(d) 123 − 12 = 111

  1. Line up from the right: 2 under 3, 1 under 2.
  2. Ones: 3 − 2 = 1. Tens: 2 − 1 = 1. Hundreds: 1 stays.

(e) 77,777 − 777 = 77,000

  1. Ones: 7 − 7 = 0. Tens: 7 − 7 = 0. Hundreds: 7 − 7 = 0.
  2. Thousands: 7 stays. Ten-thousands: 7 stays.

(f) 826 − 752 = 74

  1. Ones: 6 − 2 = 4.
  2. Tens: 2 is smaller than 5. Take 1 hundred from the 8 hundreds. Tens become 12, hundreds become 7. 12 − 5 = 7.
  3. Hundreds: 7 − 7 = 0, so nothing is written there.
Tip: In (d) the danger is lining 12 up under 123 from the left. Always start from the ones end.
Q2.
Mary's train journey to Delhi. Mary is on a train journey. She starts from Kolkata with ₹12,540. She spends ₹3,275 on food and other expenses during her trip to Varanasi. In Varanasi, her uncle gives her a gift worth ₹4,900. She then travels to Delhi, spending ₹2,645 on the train ticket. She spends ₹1,275 on souvenirs in Delhi. How much money is Mary left with at the end of the Delhi trip?
Answer

Mary is left with ₹10,245.

Follow her purse stop by stop. Money spent is taken away; the gift is added.

StageWhat happensMoney in hand
Leaves Kolkatastarting amount₹12,540
Reaches Varanasispends ₹3,275₹9,265
In Varanasigift of ₹4,900 added₹14,165
Ticket to Delhispends ₹2,645₹11,520
In Delhispends ₹1,275₹10,245
  1. 12,540 − 3,275 = 9,265
  2. 9,265 + 4,900 = 14,165
  3. 14,165 − 2,645 = 11,520
  4. 11,520 − 1,275 = 10,245
Money left with Mary = ₹10,245
Why we work stop by stop: Each stop changes only one thing. Doing them one at a time keeps the numbers small and lets you see, at every station, exactly how much Mary is carrying.
Check it yourself, a second way: Money coming in = 12,540 + 4,900 = 17,440. Money going out = 3,275 + 2,645 + 1,275 = 7,195. Left over = 17,440 − 7,195 = ₹10,245 ✓
Q3.
Members of a school council have raised ₹70,500. They plan to set up a Maths Lab with some games and models worth ₹39,785, buy library books worth ₹9,545, and purchase sports equipment worth ₹19,548. (a) Estimate whether the school council has raised enough money to make the purchases. Share your thoughts in the class. (b) Check your estimate with calculations.
Answer

(a) Estimate — yes, but only just.

  1. Round each cost to the nearest thousand: ₹39,785 → about ₹40,000; ₹9,545 → about ₹10,000; ₹19,548 → about ₹20,000.
  2. Add the rounded costs: 40,000 + 10,000 + 20,000 = ₹70,000.
  3. They have ₹70,500. That is a little more than ₹70,000.
  4. So it looks like they can just manage it — but the gap is small, so we must check properly.

Sample answer for the class discussion: "Each of the three costs is a little under the round number I used — 39,785 is below 40,000, 9,545 is below 10,000 and 19,548 is below 20,000. So the real total will be a bit less than ₹70,000, and ₹70,500 should be enough."

(b) The exact calculation — yes, and ₹1,622 is left over.

  1. 39,785 + 9,545 = 49,330
  2. 49,330 + 19,548 = 68,878  (total cost)
  3. 70,500 − 68,878 = 1,622
Total cost = ₹68,878
Money raised = ₹70,500
Money left over = ₹1,622
Check it yourself: 68,878 + 1,622 = 70,500 ✓ The estimate said "just enough", and the exact sum agrees.
Q4.
A truck can carry 8,250 kg of goods. A factory loads 3,675 kg of cement and 2,850 kg of steel on it. (a) What is the total weight loaded onto the truck? (b) How much more weight can the truck carry before reaching its maximum capacity?
Answer

(a) 6,525 kg is already loaded. (b) 1,725 kg more can still be loaded.

(a) Total weight loaded

Cement and steel are both sitting on the truck, so we add them.

  1. Ones: 5 + 0 = 5.
  2. Tens: 7 + 5 = 12. Write 2, carry 1.
  3. Hundreds: 6 + 8 + 1 = 15. Write 5, carry 1.
  4. Thousands: 3 + 2 + 1 = 6.
3,675 kg + 2,850 kg = 6,525 kg

(b) Weight the truck can still take

The truck can hold 8,250 kg in all. Take away what is already on it.

  1. Ones: 0 is smaller than 5. Take 1 ten from the 5 tens. Ones become 10, tens become 4. 10 − 5 = 5.
  2. Tens: 4 − 2 = 2.
  3. Hundreds: 2 is smaller than 5. Take 1 thousand from the 8 thousands. Hundreds become 12, thousands become 7. 12 − 5 = 7.
  4. Thousands: 7 − 6 = 1.
8,250 kg − 6,525 kg = 1,725 kg
Check it yourself: 6,525 + 1,725 = 8,250 ✓ — exactly the truck's full capacity.
Was this helpful?