Q1.
The cost of some grocery items is given in the following table. Find the total cost of each item.
The grocery table printed on page 112. The last column is empty — that is what you have to find.
| Item | Weight | Cost of 1 kg | Total cost |
|---|---|---|---|
| Rice | 12 kg 500 g | ₹ 60 | |
| Flour | 7 kg 250 g | ₹ 40 | |
| Sugar | 5 kg | ₹ 45 | |
| Chana dal | 3 kg 600 g | ₹ 70 | |
| Besan | 4 kg | ₹ 60 | |
| Jaggery | 1 kg 400 g | ₹ 50 |
Answer
Rice ₹750, Flour ₹290, Sugar ₹225, Chana dal ₹252, Besan ₹240, Jaggery ₹70.
For each item, work out the cost of the whole kilograms first, then the cost of the extra grams, and add.
- Cost of the whole kilograms = number of kg × cost of 1 kg.
- Cost of the extra grams: 500 g is half a kilogram, 250 g is one-fourth, 400 g is four-tenths, 600 g is six-tenths. Take that share of the 1 kg price.
- Add the two parts.
| Item | Weight | Cost of 1 kg | Working | Total cost |
|---|---|---|---|---|
| Rice | 12 kg 500 g | ₹60 | 12 × 60 = 720; half of 60 = 30; 720 + 30 | ₹750 |
| Flour | 7 kg 250 g | ₹40 | 7 × 40 = 280; one-fourth of 40 = 10; 280 + 10 | ₹290 |
| Sugar | 5 kg | ₹45 | 5 × 45 | ₹225 |
| Chana dal | 3 kg 600 g | ₹70 | 3 × 70 = 210; 600 g costs 6 × 7 = 42; 210 + 42 | ₹252 |
| Besan | 4 kg | ₹60 | 4 × 60 | ₹240 |
| Jaggery | 1 kg 400 g | ₹50 | 1 × 50 = 50; 400 g costs 4 × 5 = 20; 50 + 20 | ₹70 |
Where “6 × 7” comes from: 100 g is one tenth of a kilogram. So 100 g of chana dal costs ₹70 ÷ 10 = ₹7. Then 600 g costs 6 × ₹7 = ₹42. The same idea gives jaggery: 100 g costs ₹5, so 400 g costs ₹20.
Bill total = 750 + 290 + 225 + 252 + 240 + 70 = ₹1,827
Check one of them a second way: Rice — 12 kg 500 g = 12,500 g. 1,000 g costs ₹60, so 100 g costs ₹6, so 12,500 g costs 125 × ₹6 = ₹750 ✓