Q1.
A restaurant owner uses 5 kg 200 g, 8 kg 900 g, and 12 kg 600 g of onions over 3 days. What is the total weight of onions used by the restaurant owner in 3 days?
Answer
He used 26 kg 700 g of onions in three days.
- Name what we need. The total onions for 3 days, so we add all three amounts.
- Change each to grams. 5 kg 200 g = 5,200 g; 8 kg 900 g = 8,900 g; 12 kg 600 g = 12,600 g.
- Add the grams. 5,200 + 8,900 = 14,100. Then 14,100 + 12,600 = 26,700 g.
- Change back to kg and g. 26,700 g = 26 kg 700 g.
5,200 g + 8,900 g + 12,600 g = 26,700 g
26,700 g = 26 kg 700 g
26,700 g = 26 kg 700 g
Second route (columns): kg column 5 + 8 + 12 = 25 kg. g column 200 + 900 + 600 = 1,700 g = 1 kg 700 g. Carry the 1 kg: 25 + 1 = 26 kg, and 700 g stays. 26 kg 700 g ✓ Same answer.