EN हिं

NCERT Solutions for Class 5th Maths Chapter 9 Oil, coir and tender coconuts from Susie and Sunitha's farm — Kalpavruksha Coconut Oil

Book page 126–127 Updated on2026-09-19

Q1.
1. In a particular year, Susie and Sunitha used 4376 coconuts for extracting coconut oil. They can extract 1 l of oil from 8 coconuts. What quantity of oil were they able to extract?
Answer

They extracted 547 litres of oil.

Every 8 coconuts make 1 litre. So the number of litres is the number of groups of 8 inside 4376. That is a division.

Susie's way — small chunks.

8) 4376 ( 200 + 200 + 100 + 40 + 7
 −1600 → 2776
 −1600 → 1176
  −800 →  376
  −320 →   56
   −56 →   00

200 + 200 + 100 + 40 + 7 = 547

Sunitha's way — the biggest chunk first. She thinks: 8 × 500 = 4000, and 4000 is close to 4376.

8) 4376 ( 500 + 40 + 7
 −4000 → 376
  −320 →  56
   −56 →  00

500 + 40 + 7 = 547
Check by a second route: 8 × 547 = 8 × 500 + 8 × 40 + 8 × 7 = 4000 + 320 + 56 = 4,376 ✓
Answer: 547 litres of oil.
Q2.
How much will they earn if they sell the oil at ₹175 for 1 l? They will earn ₹ 547 × 175. Find out.
Answer

They will earn ₹95,725.

547 litres, each sold at ₹175. So multiply.

Step 1 — break 175 into 100 + 70 + 5

Step 2 — multiply each part:
547 × 100 = 54,700
547 × 70 = 38,290
547 × 5 = 2,735

Step 3 — add them up:
54,700 + 38,290 = 92,990
92,990 + 2,735 = ₹95,725

The same sum written in columns:

    5 4 7
 × 1 7 5
─────────
  2 7 3 5   (547 × 5)
3 8 2 9 0   (547 × 70)
5 4 7 0 0   (547 × 100)
─────────
9 5 7 2 5
Check with an estimate: 550 × 175 is about 96,250 — very close to ₹95,725, so the answer is sensible.
Answer: ₹95,725.
Q3.
2. Coconut husk is used for making coir. Susie and Sunitha's farm sells coconut husk at ₹23 per kilogram. They earned ₹9913 from the sale of husk in May. What quantity of husk did they sell in May? What would happen if 23 is multiplied by 300 or 500?
Answer

They sold 431 kg of coconut husk in May.

Each kilogram brings ₹23. So the number of kilograms is how many 23s there are in 9913.

Make a guess first. 23 × 400 = 9200, which is close to 9913. So the answer is a bit more than 400 kg.

23) 9913 ( 400 + 30 + 1
 −9200 → 713   (23 × 400)
  −690 →   23   (23 × 30)
   −23 →   00   (23 × 1)

Quotient = 400 + 30 + 1 = 431 kg, Remainder = 0

What would happen if 23 is multiplied by 300 or 500?

Chunk tried23 × chunkWhat happens
3006,900It fits, but 3,013 would still be left — you would need extra steps. Too small a chunk.
4009,200Fits and comes closest to 9,913. Best choice.
50011,500Bigger than 9,913 — you cannot take away more than you have.
Check by a second route: 23 × 431 = 23 × 400 + 23 × 30 + 23 × 1 = 9200 + 690 + 23 = 9,913 ✓
Answer: 431 kg.
Q4.
3. In the hot summer months, tender coconuts are sold for ₹35. Ibrahim earns ₹8890 in a week. How many tender coconuts did he sell? Complete: 35) 8890 (____ + 50 + ____ . Ibrahim sold ______ tender coconuts.
Answer

Ibrahim sold 254 tender coconuts. The blanks are 200 and 4.

Every coconut brings ₹35, so the number of coconuts is how many 35s make ₹8890.

35) 8890 ( 200 + 50 + 4
 −7000 → 1890   (35 × 200 = 7000)
 −1750 →  140   (35 × 50 = 1750)
  −140 →   00   (35 × 4 = 140)

Quotient = 200 + 50 + 4 = 254, Remainder = 0

How each chunk was chosen:

  1. 35 × 200 = 7,000 fits inside 8,890. 35 × 300 = 10,500 would be too big. So the first chunk is 200.
  2. 1,890 is left. 35 × 50 = 1,750 fits. 35 × 60 = 2,100 is too big. So the next chunk is 50.
  3. 140 is left. 35 × 4 = 140 exactly. So the last chunk is 4, and nothing remains.
Check by a second route: 35 × 254 = 35 × 250 + 35 × 4 = 8,750 + 140 = ₹8,890 ✓
Answer: 254 tender coconuts.
Q5.
Ibrahim had bought the tender coconuts for ₹20 each. How much extra money did he earn by selling the coconuts at ₹35? The cost of _______ coconuts at ₹20 each = _______ × ₹20 = ₹_______. He earned ₹8890 from the sale. The extra amount he earned is ₹8890 – ₹_______ = ₹_______.
Answer

He earned ₹3,810 extra.

From the last question we know he sold 254 tender coconuts.

The cost of 254 coconuts at ₹20 each
= 254 × ₹20
= ₹5,080

He earned ₹8,890 from the sale.

Extra amount = ₹8,890 − ₹5,080 = ₹3,810

Working out 254 × 20, step by step:

  1. 254 × 2 = 508.
  2. Multiplying by 20 is multiplying by 2 and then by 10, so add a zero: 5,080.

Working out the subtraction:

8890 − 5080
= (8890 − 5000) − 80
= 3890 − 80
= ₹3,810
Why it works out this way: On every single coconut he made ₹35 − ₹20 = ₹15 profit. For 254 coconuts that is 254 × 15.
Check by that second route: 254 × 15 = 254 × 10 + 254 × 5 = 2,540 + 1,270 = ₹3,810 ✓ — the same answer.
Answer: ₹3,810 extra.
Was this helpful?