NCERT Solutions for Class 5th Maths Chapter 9 Word problems, the 1-to-8 puzzle, and fill in the blanks — Let Us Do

Book page 122 Updated on2026-09-19

Q1.
1. Sabina cycles 160 km in 20 days and the same distance each day. How many kilometres does she cycle each day?
Answer

Sabina cycles 8 km each day.

We need to find the distance for one day. The whole distance, 160 km, is shared equally over 20 days. Sharing equally means dividing.

Step 1: Distance for one day = 160 ÷ 20
Step 2: Cover one zero in each number → 16 ÷ 2
Step 3: 16 ÷ 2 = 8
Step 4: So 160 ÷ 20 = 8 km
Check by a second route: If she cycles 8 km a day for 20 days, she covers 8 × 20 = 160 km. That is exactly the distance given. ✓
Answer: 8 km each day.
Q2.
2. How many notes of ₹100 does Seema need to carry if she wants to buy coconuts worth ₹4200?
Answer

Seema needs 42 notes of ₹100.

We need to find how many ₹100 notes make ₹4200. So we ask: how many hundreds are there in 4200?

Step 1: Number of notes = 4200 ÷ 100
Step 2: Dividing by 100 removes two zeros
Step 3: 4200 ÷ 100 = 42 notes
Check by a second route: 42 notes × ₹100 = ₹4,200 ✓
Answer: 42 notes of ₹100.
Q3.
3. The owner of an electric store has decided to distribute ₹5500 equally amongst 5 of his employees as a Diwali gift. What amount will each employee get? What will happen if he distributes the same amount of money among 10 employees? Will each employee get more or less? How much money would he have to distribute if everyone must get the same amount as earlier?
Answer

With 5 employees each gets ₹1100. With 10 employees each gets only ₹550 — less. To give ₹1100 to all 10, he would need ₹11,000.

Part 1 — sharing ₹5500 among 5 people.

Step 1: Amount for one person = 5500 ÷ 5
Step 2: Split 5500 into 5000 + 500
Step 3: 5000 ÷ 5 = 1000 and 500 ÷ 5 = 100
Step 4: 1000 + 100 = ₹1,100 each

Part 2 — the same ₹5500 among 10 people.

Step 1: Amount for one person = 5500 ÷ 10
Step 2: Dividing by 10 removes one zero
Step 3: 5500 ÷ 10 = ₹550 each

So each employee gets less — in fact exactly half of ₹1,100.

Part 3 — how much money for 10 people at ₹1,100 each?

Step 1: Money needed = 1100 × 10
Step 2: Multiplying by 10 adds one zero
Step 3: Money needed = ₹11,000
Why each gets less: The money did not change, but the number of people doubled. Twice as many people sharing the same money means each person gets half as much.
Check it yourself: 10 × ₹550 = ₹5,500 ✓  and  10 × ₹1,100 = ₹11,000 ✓
Q4.
4. Place the numbers 1 to 8 in the following boxes so that all the four operations, division, multiplication, addition and subtraction are correct. No number must be repeated. How did you think about solving this? Is there more than one answer?
Answer

One correct filling: 6 ÷ 3 = 2, then 6 − 5 = 1, 2 × 4 = 8, and 1 + 7 = 8.

632 54 178 ÷= × +=
Read across the top row, down the two sides, and across the bottom row. All four sentences are true, and 1 to 8 are each used once.

The four sentences to check:

Top row: 6 ÷ 3 = 2 ✓
Left column: 6 − 5 = 1 ✓
Right column: 2 × 4 = 8 ✓
Bottom row: 1 + 7 = 8 ✓

Numbers used: 6, 3, 2, 5, 4, 1, 7, 8 — that is 1 to 8, each once ✓

How to think about it (this answers "How did you think about solving this?"):

  1. Start with the division. It is the fussiest sentence, because one number must divide the other exactly. Using only 1 to 8, the choices are few: 6 ÷ 3 = 2, 8 ÷ 4 = 2, 6 ÷ 2 = 3, 8 ÷ 2 = 4.
  2. Try 6 ÷ 3 = 2. Now 6, 3 and 2 are used up. Left over: 1, 4, 5, 7, 8.
  3. Do the subtraction next. The top-left number is 6, so 6 − ? must be a leftover number. 6 − 5 = 1, and both 5 and 1 are free. Take it.
  4. Do the multiplication. The top-right number is 2, so 2 × ? must be a leftover number. Free numbers left are 4, 7, 8. Take 2 × 4 = 8.
  5. Check the addition last. The bottom row is now 1 + ? = 8. The only number still free is 7, and 1 + 7 = 8. It fits.

Is there more than one answer? Yes. Here is a second one:

8 ÷ 4 = 2
8 − 7 = 1
2 × 3 = 6
1 + 5 = 6
Numbers used: 8, 4, 2, 7, 1, 3, 5, 6 — all of 1 to 8 ✓
Tip: In a puzzle like this, always start with the hardest condition. Addition and subtraction are easy to fix at the end; division hardly ever is.
Q5.
5. Fill in the blanks: (a) _____ ÷ 18 = 100. (b) _____ ÷ 10 = 610. (c) _____ ÷ 100 = 72. (d) _____ ÷ 100 = 10. (e) 870 ÷ _____ = 87. (f) _____ ÷ 100 = 70. (g) 200 ÷ _____ = 2. (h) 130 ÷ _____ = 13.
Answer

Use the rule N = D × Q every time.

PartQuestionWhat to doAnswer
(a)___ ÷ 18 = 10018 × 1001,800
(b)___ ÷ 10 = 61010 × 6106,100
(c)___ ÷ 100 = 72100 × 727,200
(d)___ ÷ 100 = 10100 × 101,000
(e)870 ÷ ___ = 87870 ÷ 8710
(f)___ ÷ 100 = 70100 × 707,000
(g)200 ÷ ___ = 2200 ÷ 2100
(h)130 ÷ ___ = 13130 ÷ 1310

Two different jobs here — be careful which one you have.

  1. If the dividend is missing (parts a, b, c, d, f), multiply the divisor by the quotient. For (a): 18 × 100 = 1,800.
  2. If the divisor is missing (parts e, g, h), divide the dividend by the quotient. For (e): 870 ÷ 87 = 10.
Check them all: 1800 ÷ 18 = 100 ✓   6100 ÷ 10 = 610 ✓   7200 ÷ 100 = 72 ✓   1000 ÷ 100 = 10 ✓   870 ÷ 10 = 87 ✓   7000 ÷ 100 = 70 ✓   200 ÷ 100 = 2 ✓   130 ÷ 10 = 13 ✓
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