Q1.
For each of the following angles, find another angle for which a triangle is (a) possible, (b) not possible. Find at least two different angles for each category: (a) 30° (b) 70° (c) 54° (d) 144°
Answer
The other angle must be less than 180° minus the given angle for a triangle to be possible.
| Given angle | Limit (180° – given) | Triangle possible — two choices (third angle) | Triangle not possible — two choices |
|---|---|---|---|
| (a) 30° | 150° | 50° (third 100°), 90° (third 60°) | 150°, 170° |
| (b) 70° | 110° | 60° (third 50°), 80° (third 30°) | 120°, 140° |
| (c) 54° | 126° | 90° (third 36°), 64° (third 62°) | 134°, 154° |
| (d) 144° | 36° | 20° (third 16°), 35° (third 1°) | 36°, 90° |
Sample check, (b) with 60°:
70° + 60° = 130° < 180° ✓
Third angle = 180° – 130° = 50°
70° + 60° = 130° < 180° ✓
Third angle = 180° – 130° = 50°
Why it happens: The two chosen angles must leave something over for the third angle, so their sum has to stay strictly under 180°. Angles at or above the limit leave nothing (or less than nothing) for the third angle.
Tip: In (d), because 144° is already large, the partner angle has very little room — anything from just above 0° up to just below 36°.