NCERT Solutions Curiosity Chapter 8 .1.1 A simple pendulum — Activity 8.2: Let us experiment

Book page 109 & 1108 Updated on2026-09-05

Q1.
Gently hold the bob, move it slightly to one side and release it. Take care not to push the bob while releasing it and that the string is taut. Is your pendulum now oscillating?
Answer

Yes. The bob swings from one side to the other and back again, again and again, along the same path — that is oscillatory motion, and it is periodic because the path repeats after a fixed interval of time.

Two cautions in the step decide whether the experiment will work:

  • Do not push the bob. A push gives it extra speed, the swing becomes wide and irregular, and the readings scatter.
  • Keep the string taut. A loose string makes the bob dip and jerk instead of swinging along a smooth arc, and the length of the pendulum keeps changing.
Why it does not go on for ever: air resistance and rubbing at the support take away a little energy in every swing, so the bob rises less each time and finally stops. Notice, though, that as the swing becomes smaller the time period hardly changes — which is precisely what makes a pendulum a good timekeeper.
Q2.
Is the time period of your pendulum almost the same every time? What do you conclude from this observation?
Answer

Yes, it is almost the same every time. Here is Table 8.1 with a typical set of readings for a 100 cm pendulum. Time period = (time taken for 10 oscillations) ÷ 10.

Table 8.1 Time period of a simple pendulum (Length of the string = 100 cm)
S.No.Time taken for 10 oscillations (seconds)Time period (seconds)
1.20.120.1 ÷ 10 = 2.01
2.19.919.9 ÷ 10 = 1.99
3.20.220.2 ÷ 10 = 2.02
Time period ≈ 2 s in every trial
Largest difference between trials = 2.02 s − 1.99 s = 0.03 s only

Conclusion: the time period of a simple pendulum of a given length is constant at a place. The tiny differences between readings come from our reaction time in starting and stopping the watch, not from the pendulum.

Why we time 10 oscillations and not one: a person's hand takes about 0.2 s to react. If you time one oscillation of 2 s, that error is a whole 10%. Time 10 oscillations (20 s) and the same error is spread over ten swings — it becomes 0.02 s per oscillation, i.e. only 1%. Measuring many repeats and dividing is a standard way of reducing error.
Tip: count the oscillations as 0, 1, 2, 3 … — start the watch on 'zero', not on 'one'. Counting from one gives you nine oscillations while you think you have ten.
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