NCERT Solutions Ganita Prakash (Part 1) Chapter 1 In-text Questions — Cubic Numbers

Book page 13 Updated on2026-09-05

Q1.
We know that 0, 1, 4, 5, 6, 9 are the only last digits possible for squares. What are the possible last digits of cubes?
Answer

All ten digits, 0 to 9, are possible.

Last digit of the number0123456789
Last digit of its cube0187456329
Why cubes differ from squares: Each of the ten digits gives a different last digit when cubed, so the map is one-to-one and covers all ten. With squares, 2 and 8 both give 4, 3 and 7 both give 9, and so on — the map folds two digits onto one and only six outcomes survive. That is why the units digit rules out many non-squares but rules out no cube at all.
Tip: This makes guessing cube roots easy. 4913 ends in 3, so its cube root ends in 7; the root is between 10 and 20 because 103 = 1000 and 203 = 8000, so it must be 17.
Q2.
Similar to squares, can you find the number of cubes with 1 digit, 2 digits, and 3 digits? What do you observe?
Answer

Count them directly from 13, 23, 33, … and compare with the squares.

DigitsCubesHow manySquares, for comparisonHow many
11, 821, 4, 93
227, 64216, 25, 36, 49, 64, 816
3125, 216, 343, 512, 7295100, 121, …, 96122

Observation: cubes are much rarer than squares. There are only 9 cubes below 1000, against 31 squares.

Why the thinning happens: The gap between consecutive cubes is (n+1)3 – n3 = 3n2 + 3n + 1, which grows like n2, while the gap between consecutive squares is only 2n + 1. Since the cube gaps widen far faster, fewer of them fit into any fixed stretch of numbers.
Q3.
Can a cube end with exactly two zeroes (00)? Explain.
Answer

No. A cube can end with 0 zeros, 3 zeros, 6 zeros … but never exactly 2.

103 = 1000 → 3 zeros
203 = 8000 → 3 zeros
1003 = 1000000 → 6 zeros
Why the count must be a multiple of 3: Write the number as m × 10k where m does not end in 0. Cubing gives m3 × 103k, and m3 cannot end in 0 either — if it did, 10 would divide m3, forcing both 2 and 5 into m. So the cube ends in exactly 3k zeros, always a multiple of 3. Two zeros is impossible.
Tip: Compare with squares, where the terminal zeros always come in an even count. In each case the count of zeros is multiplied by the power you are taking.
Was this helpful? Report an error