NCERT Solutions Ganita Prakash (Part 1) Chapter 1 Perfect Cubes and Consecutive Odd Numbers; Cube Roots — In-text Questions

Book page 14 Updated on2026-09-05

Q1.
Later in this series, we get the following set of consecutive numbers: 91 + 93 + 95 + 97 + 99 + 101 + 103 + 105 + 107 + 109. Can you tell what this sum is without doing the calculation?
Answer

1000, which is 103.

Count the terms: 91, 93, …, 109 → 10 consecutive odd numbers
In the pattern, a run of n consecutive odd numbers adds to n3
So the sum = 103 = 1000
Why it works: The rows use 1, then 2, then 3, … consecutive odd numbers, giving 13, 23, 33, …. A run of 10 must therefore give 103. You can also see it from the middle: the terms pair off around the centre — 91 + 109 = 200, 93 + 107 = 200, and so on, five pairs of 200, giving 5 × 200 = 1000.
Tip: Each row starts where the previous one stopped, so the runs never overlap. That is why adding all the rows up to n gives 13 + 23 + … + n3 as a single unbroken block of odd numbers.
Q2.
Let us check if 3375 is a perfect cube.
Answer

Yes, 3375 = 153.

3375 = 3 × 3 × 3 × 5 × 5 × 5
Three identical groups: (3 × 5) × (3 × 5) × (3 × 5)
= (3 × 5)3 = 153
Or as triplets: (3 × 3 × 3) × (5 × 5 × 5) = 33 × 53
Therefore ∛3375 = 15
Why three groups is the right test: Cubing m repeats every prime of m exactly three times as often. So a perfect cube is a number in which every prime occurs a multiple of 3 times, which is the same as saying the whole factorisation deals out into three identical groups. Dividing each exponent by 3 reads off the cube root.
Q3.
Is 500 a perfect cube?
Answer

No.

500 = 2 × 2 × 5 × 5 × 5
The three 5s form a triplet, but only two 2s are available
So the factors cannot be split into three identical groups

Therefore 500 is not a perfect cube.

Why one short exponent is enough to decide: In 500 = 22 × 53, the exponent of 2 is 2, which is not a multiple of 3. No rearrangement can fix that.
Check it yourself: 73 = 343 and 83 = 512, so 500 falls between two consecutive cubes. Multiplying 500 by 2 gives 1000 = 103, which is the smallest multiplier that makes it a cube.
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