NCERT Solutions Ganita Prakash (Part 1) Chapter 3 .4 I. The Mesopotamian Number System — In-text Questions

Book page 723 Updated on2026-09-05

Q1.
Can we represent this more compactly?
Answer

Yes — and the way we do it is the birth of place value.

The number on page 71 was 640, grouped as

640 = (10) × 60 + 40

Following the Egyptian idea we would draw the 60-symbol ten times over and then four 10-wedges — fourteen symbols in all. Instead, write the numeral for ten in the 60s slot and the numeral for forty in the ones slot:

<   |   <<<<
read as “ten 60s and one 40” — exactly what the equation says

The same for 7530:

7530 = (2) × 3600 + (5) × 60 + 30
Check: 7200 + 300 + 30 = 7530
Numeral:  YY  |  YYYYY  |  <<<

Once each slot has its own place, the symbols marking which power of 60 it is are no longer needed at all — the position says it. Drop them, and the numeral is as compact as it can be.

Why it happens: the compression works because no power of 60 can ever occur 60 or more times. If it did, sixty of them would be regrouped into one of the next power — the book shows this with (1) × 3600 + (70) × 60 + 2 = (2) × 602 + (10) × 60 + 2. So each slot holds a number between 0 and 59, which a handful of wedges can always write. A bounded slot is what makes place value possible.
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