(i) Each line holds 3 numbers, so an average of 10 means every row, column and diagonal must add up to 30. Take the ordinary 3 × 3 magic square (which sums to 15 in every direction) and add 5 to each entry:
| 13 | 6 | 11 |
| 8 | 10 | 12 |
| 9 | 14 | 7 |
Columns: 13 + 8 + 9 = 30, 6 + 10 + 14 = 30, 11 + 12 + 7 = 30
Diagonals: 13 + 10 + 7 = 30, 11 + 10 + 9 = 30
All nine numbers 6, 7, 8, 9, 10, 11, 12, 13, 14 are distinct ✓
(ii) Yes, and there are endless ways. The centre is forced to be 10, but everything else is free. Fill the grid like this, choosing any two numbers a and b:
| 10 + a | 10 − a − b | 10 + b |
| 10 − a + b | 10 | 10 + a − b |
| 10 − b | 10 + a + b | 10 − a |
Every row, column and diagonal here adds to 30 whatever a and b are — the a’s and b’s cancel out. Taking a = 3, b = 1 gives the grid above; taking a = 4, b = 1 gives a fresh one:
| 14 | 5 | 11 |
| 7 | 10 | 13 |
| 9 | 15 | 6 |