(i) (d) equal in all three vessels • (ii) (c) M will stick but N will not stick • (iii) (a) increase the height ‘H’ at which the tank is placed • (iv) (b) PA = PB, FA < FB
(i) In Fig. 6.21 the three vessels P, Q and R are of different shapes and widths, but they are joined to one another by tubes at the bottom. Water poured into R therefore spreads into all three. The pressure a liquid exerts depends only on the height of its column, so the water can be at rest only when the column height is the same everywhere — if one vessel had a taller column, its greater pressure would push water along the connecting tube into the others. Hence the level settles equal in all three vessels, whatever their shape or width.
(ii) A sucker sticks because pressing it out drives the air from under the cup, so the pressure inside becomes lower than the atmospheric pressure outside, and the outside air holds it down. On a flat smooth surface the rim seals properly, the air cannot creep back, and sucker M sticks. On a rough surface air leaks in continuously through the tiny gaps under the rim, the pressure inside never stays low, no pressure difference is maintained, and sucker N falls off.
(iii) Pressure at a tap depends on the height of the water column above it. Raising the tank raises that column, so the pressure on the ground floor increases. Options (c) and (d) change only how much water the tank holds, at the same height — and the quantity of water makes no difference to the pressure, as Activity 6.1 showed with a broad and a narrow pipe.
(iv) The two vessels hold water to the same level, so the height of the water column is the same and the pressure at the bottom is the same: PA = PB. But vessel B is wider, so the area of its base is larger. Since force = pressure × area, the same pressure acting on a larger base gives a larger force.
Force = Pressure × Area, and AreaB > AreaA
→ FA < FB