NCERT Solutions for Class 9th Maths Chapter 8 Think and Reflect — Fun with Fractals

Book page 189 Updated on2026-09-19

Q1.

Observe the Sierpiński triangle and try to answer the following questions. (a) How many black triangles are there in Stages 0 to 3 of Fig. 8.7? (b) Can you predict the number of black triangles at Stages 4 and 5? (c) Can you find a rule for the number of black triangles at the nth stage? (d) Suppose the area of the triangle (that is, the black region) in Stage 0 is 1 square unit. What is the area of the black region in Stages 1, 2 and 3? What will be the area of the black region in Stages 4 and 5? Find a rule for the area of the black region at the nth stage. What happens to this area as n, the number of stages, goes on increasing?

Stage 0Stage 1Stage 2Stage 3
Fig. 8.7 — Stages 0 to 3 of the Sierpiński triangle.
Answer

(a) Counting the black triangles in Fig. 8.7:

Stage 0: 1    Stage 1: 3    Stage 2: 9    Stage 3: 27

(b) Each black triangle is replaced by 3 smaller black triangles at the next stage, so the count is multiplied by 3.

Stage 4: 27 × 3 = 81    Stage 5: 81 × 3 = 243

(c) The counts 1, 3, 9, 27, 81, 243, … are a GP with first term 1 and common ratio 3, and they are the powers of 3 with the exponent equal to the stage number:

1 = 30, 3 = 31, 9 = 32, 27 = 33, 81 = 34, 243 = 35
Number of black triangles at Stage n = 3n
Recursively: t0 = 1, tn = 3 × tn–1

(d) At each stage the triangle is cut into 4 equal parts and the middle one is removed, so exactly 3/4 of the black area survives.

Stage 1: 1 × 3/4 = 3/4 = 0.75
Stage 2: (3/4) × (3/4) = 9/16 = 0.5625
Stage 3: (3/4)3 = 27/64 ≈ 0.4219
Stage 4: (3/4)4 = 81/256 ≈ 0.3164
Stage 5: (3/4)5 = 243/1024 ≈ 0.2373
Area at Stage n = (3/4)n square units
Recursively: s0 = 1, sn = (3/4) × sn–1

As n increases the area keeps being multiplied by 3/4, a number less than 1, so the black area shrinks steadily and creeps closer and closer to 0 without ever becoming 0.

Why it happens: the same figure produces two GPs pulling in opposite directions. Counting triangles multiplies by 3 (r > 1, so the count explodes); measuring area multiplies by 3/4 (0 < r < 1, so the area collapses). There is no contradiction: at each stage there are three times as many pieces, but each piece has only a quarter of the area of the piece it came from, and 3 × 1/4 = 3/4 < 1. That single number, 3/4, is why the count of pieces and the total area move opposite ways.
Did you know? the numbering starts at Stage 0, so here the exponent equals the stage number exactly — 3n and (3/4)n, with no "n – 1". Always check what the first stage is called before writing a formula.
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