NCERT Solutions for Class 9th Science Chapter 9 Atomic Foundations of Matter
Updated on 2026-09-19
About this chapter
Law of Conservation of Mass (Lavoisier, 1789): in a chemical reaction matter is neither created nor destroyed, so the total mass of the reactants equals the total mass of the products. It only looks violated in an open vessel, because a gaseous product walks off the balance pan. Law of Constant Proportions (Proust): a compound always contains the same elements in the same fixed ratio by mass, whatever its source. Pure water from a river, a borewell or the ocean is always H : O = 1 : 8 by mass. Dalton's atomic theory explains both laws with one picture — atoms are indivisible in a chemical reaction and merely rearrange, atoms of one element are identical in mass, and atoms combine in simple whole-number ratios. Atoms combine to reach a stable octet (a duplet for the K-shell). They do it in
- Chapter opener
- Let us investigate a physical change
- Let us investigate a chemical change
- Let us verify the law
- .1 Law of Conservation of Mass
- .2 Law of Constant Proportions
- .3 Dalton's Atomic Theory
- .4.1 A Molecules of elements
- .4.1 B Molecules of compounds
- .4.2 Bonding by electron transfer
Quick revision
| Term | What it means | Worked example | Where it appears |
|---|---|---|---|
| Law of Conservation of Mass | Total mass of reactants = total mass of products in a chemical reaction | 4.0 g CaCO₃ + 2.92 g HCl → 1.76 g CO₂ + 0.72 g H₂O + 4.44 g CaCl₂; 6.92 g = 6.92 g | 9.1, Activity 9.2, Example 9.1 |
| Law of Constant Proportions | A compound has a fixed composition by mass, whatever its source | 9 g of pure water always gives 1 g H and 8 g O — ratio 1 : 8 | 9.2, Example 9.3 |
| Postulate | A basic assumption accepted without formal proof, from which further ideas are built | “Atoms are indivisible particles” — Dalton | 9.3 Dalton's Atomic Theory |
| Molecule | Electrically neutral entity of more than one atom that can exist independently and shows all the properties of the substance | H₂, Cl₂, O₂, HCl, H₂O | 9.4 |
| Covalent bond | Bond formed by a shared pair of electrons between two atoms | H—H (single), O=O (double), N≡N (triple) | 9.4.1 |
| Ionic bond | Electrostatic force of attraction between oppositely charged ions formed by electron transfer | Na → Na⁺ + e⁻; Cl + e⁻ → Cl⁻; Na⁺Cl⁻ | 9.4.2 |
| Cation / anion | Positive ion (lost electrons) / negative ion (gained electrons) | Na⁺ (11 p⁺, 10 e⁻); Cl⁻ (17 p⁺, 18 e⁻); S²⁻ | 9.4.2, Table 9.1 |
| Polyatomic ion | An ion made of atoms of two or more elements | OH⁻, NO₃⁻, HCO₃⁻, CO₃²⁻, SO₃₃₂⁻, NH₄⁺ | Table 9.1 (b) |
| Criss-cross method | Swap the valencies (or charge numbers) and write them as subscripts; then divide by any common factor | Al³⁺, O²⁻ → Al₂O₃; Mg²⁺, O²⁻ → Mg₂O₂ = MgO | 9.5 |
| Prefix naming (covalent) | mono-, di-, tri-, tetra-, penta-, hexa- show how many atoms; second element ends in -ide | CO carbon monoxide, PCl₃ phosphorus trichloride, SF₆ sulfur hexafluoride | 9.4.1 C |
| Crystal lattice | Regular repeating 3-D arrangement of ions in an ionic solid | In NaCl each Na⁺ is surrounded by 6 Cl⁻ and each Cl⁻ by 6 Na⁺ | Threads of Curiosity, p. 173 |
| Molecular mass | Sum of the atomic masses of all atoms in one molecule | CO₂ = (12 u × 1) + (16 u × 2) = 44 u | 9.7 |
| Formula unit mass | Sum of the atomic masses of all atoms in one formula unit of an ionic compound | Na₂O = (23 u × 2) + (16 u × 1) = 62 u | 9.8 |
Exercises
- Chapter opener — Think It Over Page 162
- Let us investigate a physical change — Activity 9.1 Page 163
- Let us investigate a chemical change — Activity 9.2 Page 163 – 165
- Let us verify the law — Activity 9.3 Page 165
- .1 Law of Conservation of Mass — Think as a Scientist Page 1669
- .1 Law of Conservation of Mass — Pause and Ponder Page 1669
- .2 Law of Constant Proportions — Pause and Ponder Page 1679
- .3 Dalton's Atomic Theory — What if … Page 1689
- .3 Dalton's Atomic Theory — Pause and Ponder Page 1689
- .4.1 A Molecules of elements — Pause and Ponder Page 1709
- .4.1 B Molecules of compounds — Pause and Ponder Page 1719
- .4.2 Bonding by electron transfer — In-text Questions Page 1729
- .4.2 Bonding by electron transfer — What if … Page 1749
- .4.2 Bonding by electron transfer — Pause and Ponder Page 1749
- .5 Writing Chemical Formulae — Pause and Ponder Page 1779
- .6 Properties of the Ionic and the Covalent Compounds — Activity 9.4 Page 177 – 1789
- .6 Properties of the Ionic and the Covalent Compounds — In-text Questions Page 1789
- .6 Properties of the Ionic and the Covalent Compounds — Pause and Ponder Page 1799
- .7 Molecular Mass of Covalent Compounds — Pause and Ponder Page 1799
- .8 Formula Unit Mass of Ionic Compounds — Pause and Ponder Page 1809
- End-of-chapter questions — Revise, Reflect, Refine Page 181 – 183
- Project work — The Journey Beyond Page 183
- Closing question — The Quest Continues … Page 183