Solve a) Th H T O 3 6 9 5 + 4 2 0 8 The sum as printed in the book, with empty carry circles.

Th H T O 3 6 9 5 + 4 2 0 8 The sum as printed in the book, with empty carry circles. 3695 + 4208 Ones: 5 + 8 = 13 → write 3, carry 1 ten Tens: 9 + 0 + 1 = 10 → write 0, carry 1 hundred Hundreds: 6 + 2 + 1 = 9 Thousands: 3 + 4 = 7 = 7903 Th H T O 1 1 3 6 9 5 + 4 2 0 8 7 9 0 3 The completed sum. Why it happens: Two carries happen one after the other, because the ones made a full ten and then the tens made a full hundred.

Solve c) Th H T O 6 3 5 2 − 3 5 2 1 The subtraction as printed in the book.

Th H T O 6 3 5 2 − 3 5 2 1 The subtraction as printed in the book. 6352 − 3521 Ones: 2 − 1 = 1 Tens: 5 − 2 = 3 Hundreds: 3 − 5 cannot be done → take 1 thousand, 1 Th = 10 H , 13 − 5 = 8 Thousands: 5 − 3 = 2 = 2831 Th H T O 5 13 6 3 5 2 − 3 5 2 1 2 8 3 1 The completed subtraction, with the borrow shown. Why it happens: We borrowed one thousand and changed it into ten hundreds, so 3 hundreds became 13 hundreds. Check it yourself: 2831 + 3521 = 6352.

Solve d) Th H T O 8 8 0 3 − 5 7 2 6 The subtraction as printed in the book.

Th H T O 8 8 0 3 − 5 7 2 6 The subtraction as printed in the book. 8803 − 5726 Ones: 3 − 6 cannot be done. Tens is 0, so borrow from hundreds. 8 hundreds → 7 hundreds and 10 tens 10 tens → 9 tens and 10 ones 13 − 6 = 7 Tens: 9 − 2 = 7 Hundreds: 7 − 7 = 0 Thousands: 8 − 5 = 3 = 3077 Th H T O 8 7 9 13 8 8 0 3 − 5 7 2 6 3 0 7 7 The completed subtraction, with both borrows shown. Why it happens: There were no tens to borrow from, so we first broke one hundred into ten tens and then broke one of those tens into ten ones. Check it yourself: 3077 + 5726 = 8803.

NCERT Solutions for Class 4th Maths Chapter 10 Working in the place-value columns — Let Us Solve

Book page 161 Updated on2026-09-19

Q1.

Solve a)

Th	H	T	O

3	6	9	5
+ 4	2	0	8

The sum as printed in the book, with empty carry circles.

Answer

Th	H	T	O

3	6	9	5
+ 4	2	0	8

The sum as printed in the book, with empty carry circles.

3695 + 4208
Ones: 5 + 8 = 13 → write 3, carry 1 ten
Tens: 9 + 0 + 1 = 10 → write 0, carry 1 hundred
Hundreds: 6 + 2 + 1 = 9
Thousands: 3 + 4 = 7
= 7903

Th	H	T	O
	1	1
3	6	9	5
+ 4	2	0	8
7	9	0	3

The completed sum.

Why it happens: Two carries happen one after the other, because the ones made a full ten and then the tens made a full hundred.

Q2.

Solve b)

Th	H	T	O

2	5	0	7
+ 6	8	4	7

The sum as printed in the book, with empty carry circles.

Answer

Th	H	T	O

2	5	0	7
+ 6	8	4	7

The sum as printed in the book, with empty carry circles.

2507 + 6847
Ones: 7 + 7 = 14 → write 4, carry 1 ten
Tens: 0 + 4 + 1 = 5
Hundreds: 5 + 8 = 13 → write 3, carry 1 thousand
Thousands: 2 + 6 + 1 = 9
= 9354

Th	H	T	O
1		1
2	5	0	7
+ 6	8	4	7
9	3	5	4

The completed sum.

Why it happens: A carry is just a full bundle of ten moving one place to the left.

Q3.

Solve c)

Th	H	T	O

6	3	5	2
− 3	5	2	1

The subtraction as printed in the book.

Answer

Th	H	T	O

6	3	5	2
− 3	5	2	1

The subtraction as printed in the book.

6352 − 3521
Ones: 2 − 1 = 1
Tens: 5 − 2 = 3
Hundreds: 3 − 5 cannot be done → take 1 thousand, 1 Th = 10 H, 13 − 5 = 8
Thousands: 5 − 3 = 2
= 2831

Th	H	T	O
5	13
6	3	5	2
− 3	5	2	1
2	8	3	1

The completed subtraction, with the borrow shown.

Why it happens: We borrowed one thousand and changed it into ten hundreds, so 3 hundreds became 13 hundreds.

Check it yourself: 2831 + 3521 = 6352.

Q4.

Solve d)

Th	H	T	O

8	8	0	3
− 5	7	2	6

The subtraction as printed in the book.

Answer

Th	H	T	O

8	8	0	3
− 5	7	2	6

The subtraction as printed in the book.

8803 − 5726
Ones: 3 − 6 cannot be done. Tens is 0, so borrow from hundreds.
    8 hundreds → 7 hundreds and 10 tens
    10 tens → 9 tens and 10 ones
    13 − 6 = 7
Tens: 9 − 2 = 7
Hundreds: 7 − 7 = 0
Thousands: 8 − 5 = 3
= 3077

Th	H	T	O
8	7	9	13
8	8	0	3
− 5	7	2	6
3	0	7	7

The completed subtraction, with both borrows shown.

Why it happens: There were no tens to borrow from, so we first broke one hundred into ten tens and then broke one of those tens into ten ones.

Check it yourself: 3077 + 5726 = 8803.

Q5.

Arrange the following in columns and solve in your notebook. a) 3683 – 971 b) 8432 – 46 c) 4011 – 3666 d) 5203 – 2745 e) 1465 + 632 f) 3567 + 77 g) 8263 + 3737 h) 5429 + 3287

Answer

Write ones under ones, tens under tens, and so on. Then work from the right.

	Sum	What to watch for	Answer
a)	3683 − 971	971 has no thousands digit; put 0 there	2712
b)	8432 − 46	46 is only tens and ones; line it up on the right	8386
c)	4011 − 3666	borrow three times	345
d)	5203 − 2745	borrow across the 0 in the tens	2458
e)	1465 + 632	only one carry, in the tens	2097
f)	3567 + 77	77 sits in the tens and ones	3644
g)	8263 + 3737	carries all the way across	12000
h)	5429 + 3287	carry in ones, tens and hundreds	8716

Two of them worked out in full:

c) 4011 − 3666
Ones: 11 − 6 = 5 Tens: 0 → 10, 10 − 6 = 4
Hundreds: 9 − 6 = 3 Thousands: 3 − 3 = 0
= 345

h) 5429 + 3287
9 + 7 = 16 carry 1; 2 + 8 + 1 = 11 carry 1; 4 + 2 + 1 = 7; 5 + 3 = 8
= 8716

Did you know? Part (g) gives 12000, which has five digits. That is one digit more than the four-digit numbers this chapter works with. The answer is still correct — 8263 + 3737 = 12000.

Why it happens: Lining up the places is the whole trick. If the ones do not sit under the ones, every column goes wrong.

Was this helpful?