NCERT Solutions for Class 4th Maths Chapter 3 Even numbers and odd numbers — In-text Questions

Book page 36 Updated on2026-09-19

Q1.
Describe Shiv’s arrangement and write his numbers.
4
Shiv’s coin packs. One triangle is already filled in.
Answer
4
Shiv’s coin packs. One triangle is already filled in.

Shiv’s arrangement: he puts his coins two side by side, row after row. Every row is full. When he finishes a pack, no coin is left alone.

His numbers are:

4, 14, 12, 6, 8

Written from the smallest to the biggest: 4, 6, 8, 12, 14.

Every one of them can be split into pairs:

  • 4 = 2 pairs
  • 6 = 3 pairs
  • 8 = 4 pairs
  • 12 = 6 pairs
  • 14 = 7 pairs
Why it happens: A number that fills every row of two can be shared equally between two children. Such numbers are called even numbers.
Tip: To test any number, keep taking away 2. If you end at 0, the number is even.
Q2.
Describe Shirley’s arrangement and write her numbers.
35
Shirley’s coin packs. Two triangles are already filled in.
Answer
35
Shirley’s coin packs. Two triangles are already filled in.

Shirley’s arrangement: she also puts her coins two side by side. But in every pack the last row has only one coin. One coin is always left over.

Her numbers are:

3, 11, 17, 1, 7, 5

Written from the smallest to the biggest: 1, 3, 5, 7, 11, 17.

6 → 3 pairs7 → 3 pairs, 1 left
Making pairs: 6 pairs off fully, 7 always leaves one out.

Each of her numbers is some pairs and then one extra:

  • 3 = 1 pair + 1
  • 5 = 2 pairs + 1
  • 7 = 3 pairs + 1
  • 11 = 5 pairs + 1
  • 17 = 8 pairs + 1
  • 1 = no pair at all, just 1
Why it happens: A number that leaves one out cannot be shared equally between two children. Such numbers are called odd numbers.
Tip: Shiv’s numbers and Shirley’s numbers sit next to each other on the number line: 1, 2, 3, 4, 5, 6 … one odd, one even, turn by turn.
Q3.
Identify numbers between 1 and 20 as even or odd. You may draw the pairing arrangement of the numbers.
OddEven
The two boxes printed in the book, waiting to be filled.
Answer
OddEven
The two boxes printed in the book, waiting to be filled.

Try to make pairs out of each number. If one is left out, the number is odd.

Odd1, 3, 57, 9, 1113, 15, 1719Even2, 4, 68, 10, 1214, 16, 1820
The same two boxes, filled in.
Odd1, 3, 5, 7, 9, 11, 13, 15, 17, 19
Even2, 4, 6, 8, 10, 12, 14, 16, 18, 20

Here is the pairing for two of them:

6 → 3 pairs7 → 3 pairs, 1 left
Making pairs: 6 pairs off fully, 7 always leaves one out.

There are 10 odd numbers and 10 even numbers from 1 to 20. They take turns: 1 odd, 2 even, 3 odd, 4 even …

Why it happens: Every time we add 1 to a number, the coin that was left alone gets a partner, or a new coin is left alone. So even and odd must keep changing turn by turn.
Tip: If the question means only the numbers strictly between 1 and 20, leave out 1 and 20. You then get 9 odd numbers and 9 even numbers.
Q4.
Do you think all numbers in the times-2 table are even?
Answer

Yes. Every number in the times-2 table is an even number.

2 × 1 = 2    2 × 2 = 4    2 × 3 = 6    2 × 4 = 8    2 × 5 = 10
2 × 6 = 12   2 × 7 = 14   2 × 8 = 16   2 × 9 = 18   2 × 10 = 20

Look at the ones digit of each answer: 2, 4, 6, 8, 0, 2, 4, 6, 8, 0. It is always 0, 2, 4, 6 or 8 — so every answer is even.

Why it happens: The times-2 table is made by taking 2s. 2 × 7 means 7 pairs of coins. Pairs can never leave a single coin out, so the answer must be even.
Check it yourself: Lay out 2 × 9 = 18 buttons as nine rows of two. Not one button is left alone.
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