Both solids have 30 edges.
The counting trick — count face by face, then halve
- Count the edges of one face. A triangle has 3; a pentagon has 5.
- Multiply by the number of faces. Icosahedron: 20 × 3 = 60. Dodecahedron: 12 × 5 = 60.
- Notice the double counting. Every edge of the solid is shared by exactly 2 faces, so each one has been counted twice.
- Divide by 2. 60 ÷ 2 = 30 for each solid.
Icosahedron: (20 × 3) ÷ 2 = 60 ÷ 2 = 30 edges
Dodecahedron: (12 × 5) ÷ 2 = 60 ÷ 2 = 30 edges
A second way, if you would rather count on the model:
- Put a small pencil mark on each edge as you count it.
- Work in rings — first all the edges round the top vertex, then the ring below, and so on.
- An edge with a mark on it has already been counted, so skip it.
Why dividing by 2 is right: An edge is the line where two faces meet, like the crease between two walls of a room. When you go round face by face, both of those faces claim the same crease. Halving removes the double claim.
Check with Euler's rule: For any such solid, faces + vertices − edges = 2. Icosahedron: 20 + 12 − 30 = 2 ✓ Dodecahedron: 12 + 20 − 30 = 2 ✓ Try it on a cube too: 6 + 8 − 12 = 2 ✓