NCERT Solutions Ganita Prakash Chapter 3 Figure it Out — Clock and Calendar Numbers

Book page 64 & 65 Updated on2026-09-05

Q1.
Pratibha uses the digits ‘4’, ‘7’, ‘3’ and ‘2’, and makes the smallest and largest 4-digit numbers with them: 2347 and 7432. The difference between these two numbers is 7432 – 2347 = 5085. The sum of these two numbers is 9779. Choose 4-digits to make: a. the difference between the largest and smallest numbers greater than 5085. b. the difference between the largest and smallest numbers less than 5085. c. the sum of the largest and smallest numbers greater than 9779. d. the sum of the largest and smallest numbers less than 9779.
Answer

Pick four digits, arrange them in decreasing order for the largest number and in increasing order for the smallest.

a. Difference greater than 5085 → choose digits that are far apart, such as 9, 8, 1, 0.

Largest = 9810,   Smallest = 1089
9810 − 1089 = 8721   and 8721 > 5085 ✓

b. Difference less than 5085 → choose digits that are close together, such as 5, 4, 3, 2.

Largest = 5432,   Smallest = 2345
5432 − 2345 = 3087   and 3087 < 5085 ✓

c. Sum greater than 9779 → choose big digits, such as 9, 8, 7, 6.

Largest = 9876,   Smallest = 6789
9876 + 6789 = 16,665   and 16,665 > 9779 ✓

d. Sum less than 9779 → choose small digits, such as 4, 3, 2, 1.

Largest = 4321,   Smallest = 1234
4321 + 1234 = 5555   and 5555 < 9779 ✓
Why this works: the difference depends on how spread out the digits are — 9 and 0 together give a big difference. The sum depends on how big the digits themselves are — four large digits give a large sum.
Q2.
What is the sum of the smallest and largest 5-digit palindrome? What is their difference?
Answer

The smallest 5-digit palindrome is 10001 (it must start with 1 and end with 1, with zeros in between) and the largest is 99999.

Sum = 10,001 + 99,999 = 1,10,000
Difference = 99,999 − 10,001 = 89,998
Check it yourself: 10001 read backwards is 10001 ✓ and 99999 backwards is 99999 ✓ — both are palindromes.
Q3.
The time now is 10:01. How many minutes until the clock shows the next palindromic time? What about the one after that?
Answer

10:01 is itself a palindrome (1001 read backwards is 1001). The palindromic times that come next are 11:11 and then 12:21.

From 10:01 to 11:11 → 1 hour 10 minutes = 60 + 10 = 70 minutes
From 11:11 to 12:21 → 1 hour 10 minutes = 70 minutes
From 10:01 to 12:21 → 2 hours 20 minutes = 120 + 20 = 140 minutes

Answer: 70 minutes to the next palindromic time (11:11), and the one after that (12:21) comes 140 minutes after 10:01.

Why nothing in between: between 10:01 and 11:11 the clock shows 10:02, 10:03 … 11:10. For a 4-digit time to be a palindrome the minutes must be the hour written backwards — 10:01, 11:11, 12:21 — and no other reading in this stretch does that.
Q4.
How many rounds does the number 5683 take to reach the Kaprekar constant?
Answer

Each round means: make the largest number A, make the smallest number B, and work out C = A − B.

RoundLargest (A)Smallest (B)C = A − B
1865335685085
2855050583492
3943223497083
4873030785652
5655225563996
6996336996264
7664224664176
8764114676174

Answer: 8 rounds.

Tip: in round 2 the digits are 5, 0, 8, 5. The smallest 4-digit number from them is 5058, because a number cannot begin with 0. (If you do allow 0558, you reach 6174 in 7 rounds instead — either way you always get there.)
Was this helpful? Report an error