NCERT Solutions Ganita Prakash Chapter 6 Charan’s house plan — In-text Questions
Book page 146 Updated on2026-09-05
Q1.
Below is the house plan of Charan. It is in a rectangular plot. Look at the plan. What do you notice? Some of the measurements are given. a. Find the missing measurements.
Answer
What we notice first: the whole plot is a rectangle, and every room inside it is a rectangle too. So the rooms in each column must add up to the height of the plot, and the rooms in each row must add up to its width. That is enough to find every missing number.
Step 1 — the width of the plot. The left column (Master Bedroom) is 15 ft wide, the Toilet strip is 5 ft wide and the Kitchen column is 15 ft wide.
Width = 15 + 5 + 15 = 35 ft (the height 30 ft is given)
Step 2 — go column by column.
Left column: 15 (bedroom) + Small Bedroom + Garden = 30
Small Bedroom: area 180 = 15 × ? → ? = 12 ft
So the Garden strip is 30 − 15 − 12 = 3 ft high
Right column: Utility + 12 (kitchen) + Hall + 3 (parking) = 30 → Utility = 3 ft high
Charan's completed plan. Every room is filled in; the small 5 ft × 5 ft space is the passage joining the toilet to the hall.
Room
Dimensions
Area
Master Bedroom
15 ft × 15 ft
225 sq ft
Toilet
5 ft × 10 ft
50 sq ft
Utility
15 ft × 3 ft
45 sq ft
Kitchen
15 ft × 12 ft
180 sq ft
Small Bedroom
15 ft × 12 ft
180 sq ft
Hall
20 ft × 12 ft
240 sq ft
Garden
20 ft × 3 ft
60 sq ft
Parking
15 ft × 3 ft
45 sq ft
Note: the Hall is 20 ft wide because it stretches across the 5 ft middle strip and the 15 ft right column (5 + 15 = 20). The Garden does the same on the left: 15 + 5 = 20 ft.
Q2.
b. Find out the area of his house.
Answer
The plot is a rectangle 35 ft by 30 ft.
Area of the house = 35 ft × 30 ft = 1050 sq ft
Check by adding the rooms:
225 + 50 + 45 + 180 + 180 + 240 + 60 + 45 = 1025 sq ft
+ the 5 ft × 5 ft passage (25 sq ft) = 1050 sq ft ✔