NCERT Solutions Ganita Prakash (Part 1) Chapter 3 In-text Questions — Addition and Subtraction of Decimals

Book page 75 Updated on2026-09-05

Q1.
Write the detailed place value computation for 84.691 – 77.345, and its compact form.
Answer

Detailed place value form

84.691 = 8 × 10 + 4 × 1 + 6 × 110 + 9 × 1100 + 1 × 11000
77.345 = 7 × 10 + 7 × 1 + 3 × 110 + 4 × 1100 + 5 × 11000

Thousandths: 1 – 5 → borrow 1 hundredth
  9 hundredths → 8 hundredths, thousandths become 11
  11 – 5 = 6 thousandths
Hundredths: 8 – 4 = 4 hundredths
Tenths: 6 – 3 = 3 tenths
Ones: 4 – 7 → borrow 1 ten
  8 tens → 7 tens, ones become 14
  14 – 7 = 7 ones
Tens: 7 – 7 = 0 tens
= 0 × 10 + 7 × 1 + 3 × 110 + 4 × 1100 + 6 × 11000

Compact form

  84.691
– 77.345
=  7.346
Why it happens: only two borrowings are needed — one from the hundredths into the thousandths, and one from the tens into the ones. The tenths and hundredths columns subtract without any trouble.
Check it yourself: 7.346 + 77.345 = 84.691 ✓
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