NCERT Solutions for Class 8th Maths Chapter 6 We Distribute, Yet Things Multiply

Updated on 2026-09-19

About this chapter

Distributivity, a (b + c) = ab + ac , is the one rule the whole chapter rests on. Read as an area picture, an a × ( b + c ) array splits into an a × b array and an a × c array. Applying it twice gives Identity 1: (a + m)(b + n) = ab + mb + an + mn — every term of the first bracket times every term of the second. Because the rules of integer multiplication handle the signs, the same identity also covers decreases: just take m or n negative. Three special cases are named in the chapter — 1A: (a + b)² = a² + 2ab + b², 1B: (a – b)² = a² + b² – 2ab, 1C: (a + b)(a – b) = a² – b². Each is proved twice: by expanding, and by cutting up a square. The same identities give fast mental arithmetic: 65² from 60² and 5², 397 × 403 from 400² – 3², and Sridharacharya's trick a² = (a + b)(a – b) + b². Sectio

  • .1 Some Properties of Multiplication
  • Fast Multiplications Using the Distributive Property
  • .2 Special Cases of the Distributive Property
  • Investigating Patterns
  • .3 Mind the Mistake, Mend the Mistake
  • .4 This Way or That Way, All Ways Lead to the Bay
  • Coin Conjoin
Quick revision
NameIdentityWorked exampleWhere the chapter uses it
Distributivitya (b + c) = ab + ac23 (27 + 1) = 23 × 27 + 23Increase in a product when one factor grows
Right form(a + b) c = ac + bc(20 + 3) × 7 = 140 + 21 = 161Brahmagupta's khaṇḍa-guṇanam
Identity 1(a + m)(b + n) = ab + mb + an + mn(a + 1)(b + 1) = ab + a + b + 1Any increase or decrease in both factors
Identity 1 with n negative(a + u)(b – v) = ab + ub – av – uv(a + 1)(b – 1) = ab + b – a – 1One factor up, the other down
Identity 1A(a + b)² = a² + 2ab + b²65² = 3600 + 600 + 25 = 4225Square of a sum; 104², 46²
Identity 1B(a – b)² = a² + b² – 2ab55² = 3600 + 25 – 600 = 3025Square of a difference; 99², 91²
Identity 1C(a + b)(a – b) = a² – b²397 × 403 = 400² – 3² = 159991Pattern 2; 45 × 55; 98 × 102
Sum of two squares2(a² + b²) = (a + b)² + (a – b)²2(5² + 6²) = 11² + 1²Pattern 1
Sridharacharyaa² = (a + b)(a – b) + b²31² = 32 × 30 + 1 = 961Fast squaring
Multiply by 11N × 11 = N × 10 + N495 × 11 = 4|13|14|5 = 5445Add neighbouring digits
Multiply by 101N × 101 = N × 100 + N89 × 101 = 8989Add digits two places apart
Multiply by 99, 999N × 99 = N × 100 – N9734 × 99 = 973400 – 9734 = 963666Same rule, subtraction form
Read the chapter
  1. .1 Some Properties of Multiplication — In-text Questions Page 1366
  2. .1 Some Properties of Multiplication — In-text Questions Page 1386
  3. .1 Some Properties of Multiplication — In-text Questions Page 1396
  4. .1 Some Properties of Multiplication — In-text Questions Page 1406
  5. .1 Some Properties of Multiplication — In-text Questions Page 1416
  6. .1 Some Properties of Multiplication — Figure it Out Page 1426
  7. Fast Multiplications Using the Distributive Property — In-text Questions Page 143
  8. Fast Multiplications Using the Distributive Property — In-text Questions Page 144
  9. .2 Special Cases of the Distributive Property — In-text Questions Page 1456
  10. .2 Special Cases of the Distributive Property — In-text Questions Page 1466
  11. .2 Special Cases of the Distributive Property — In-text Questions Page 1476
  12. Investigating Patterns — In-text Questions Page 148
  13. Investigating Patterns — In-text Questions Page 149
  14. Investigating Patterns — Figure it Out Page 149
  15. .3 Mind the Mistake, Mend the Mistake — Mind the Mistake, Mend the Mistake Page 1506
  16. .4 This Way or That Way, All Ways Lead to the Bay — In-text Questions Page 1506
  17. .4 This Way or That Way, All Ways Lead to the Bay — In-text Questions Page 1526
  18. .4 This Way or That Way, All Ways Lead to the Bay — In-text Questions Page 1536
  19. .4 This Way or That Way, All Ways Lead to the Bay — In-text Questions Page 1546
  20. .4 This Way or That Way, All Ways Lead to the Bay — Figure it Out Page 1546
  21. Coin Conjoin — Puzzle Time: Coin Conjoin Page 158
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